fruit math

[ilikexd]

what's the answer to this? my friend and i got different answers

[Frank Munoz]

a bit of a crude trick, huh?
iono if you really want me to elaborate on it or see other peoples reactions first. I'll wait.

[Mourningfall]

9 or 14, leaning towards 9 because lol math

[MinaciousGrace]

moot frath

[Mr.Burner]

17

[GammaBlaster]

saw 17, then I looked very closely at the last set of fruit and now

aaaaaaaaaaaaaaaaaaaaaaaaa

edit: ok nathan I see you editing the OP day by day nice try

[Frank Munoz]

This problem is a modified version of this one I believe.
I think someone just grabbed some stock photos to make this, and badly erased part of the hand of bananas in the last equation to mess with people.
-the coconuts are also skewed in the second equation-
Then other manipulations came in, eventually coming to what we have here.

1.
From what I've seen, this is the 'go-to' method to solve the other version.
-maybe not the exact process, but the outcome is what the majority gets-

A+A+A=30
A+4B+4B=18
4B-2C=2
C+A+3B=??

A=10
B=1
C=1

??=14

makes some sense, right?
each banana on the hand counts as 1, and one side of the split coconut equals 1.
Though we cannot really prove that the split coconut is cut directly in half, it is heavily implied that it is. Which, imo isn't enough info, but for the generalization of a numerical answer it is understandable.

2.
For the problem provided in this thread though, the possible outcomes become more ambiguous due to the apple without-a-leaf in the last equation.
If we are to take what we learned from the other version,
the equation would be something like this

A+A+A=30
A+4B+4B=18
4B-2C=1
C+a+3B=??

A=10
B=1
C=1.5
a<10

??<14.5

Though we did generalize one side of the split coconut to equal 1, and one banana to also equal 1, we can not do the same for the apple with no leaf as it is too obscure.
What we can assume is that the no leaf apple is probably less than the leafed one... probably.

3.
In reality, the last equation uses images that are similar but are not exact to the ones used in the first three.
Meaning there is not enough information to solve for "??", or any of the three images provided to solve for "??".
Like... the images are close,
kinda like how 9 is pretty close to 10.
or how a black-flag on Max forever is pretty close to an AAA.
and how close these images are to each other can only be determined by speculation.
Which just isn't good enough to give a precise answer.
But we can almost safely say that the three images in the last equation equal something less than those above them.

final answer

A+A+A=30
A+B+B=18
B-C=1
c+a+b=??

A=10
B=4
C=3
a<10
b<4
c<3

??<17

or, anything ranging from -infinity to infinity
as there is no real indication of the images being.. anything really.


edit: OP changed the picture so this will most likely confuse yall now

[SC_coolguy44]

The way it's designed I think the answer is 15.

[SKG_Scintill]

that apple without a leaf looks very symmetrical
even I can mirror an apple with paint
so bad

[Dynam0]

it's pi you dunbies

[cedolad]

pineapple

[botchi246]

14.5

[danceflashrevo]

15-L where L is an indeterminate value of leaf that can range from 0-10.

[ilikexd]

Originally Posted by danceflashrevo

15-L where L is an indeterminate value of leaf that can range from 0-10.

Actually I think the leaf should be able to be less than 0 or greater than 10 (since you can just sum it with the base of the apple to equal 10).

So I guess the answer would be 5s/8 + 29/2, where 's' is the value of the leaf.

3a=30
a-s+8b=18
4b-2c=1
c+a+3b=x

3a=30
a=10

a-s+8b=18
10-s+8b=18
8b-s=8
8b=8+s
b=1+s/8

4b-2c=1
4(1+s/8)-2c=1
4+s/2-2c=1
3+s/2=2c
s/4+3/2=c

c+a+3b=x
s/4 + 3/2 + 10 + 3(1+s/8)=x
s/4 + 3/2 + 10 + 3 + 3s/8 = x
5s/8 + 29/2 = x

or a different solution

[danceflashrevo]

however if we give the leaf a negative value, does it even exist? thats like saying it has negative mass, and since the value is representing a piece of mass it should be positive.

perhaps this problem is past us, maybe we need to send it to the theoretical physics team, they've had a pretty good discovery recently maybe they'll discover the answer to this too.

[SKG_Scintill]

Originally Posted by danceflashrevo

however if we give the leaf a negative value, does it even exist?

seedless grapes

[danceflashrevo]

Originally Posted by SKG_Scintill

seedless grapes

okay, seedless grapes. really if we define a normal grape as a grape, then a seedless grape is grape-seed. you're subtracting the positive mass of the seed. Or perhaps a grape is seed + grape and seedless grape is just grape. still positive seed mass being shown in both cases.

[SKG_Scintill]

seedless grapes have much higher value when it comes to tastiness

[danceflashrevo]

Originally Posted by SKG_Scintill

seedless grapes have much higher value when it comes to tastiness

but are we looking at tastiness or just mass? because if we're looking at tastiness we would not be able to find a definite value. in the fruits given (coconuts, apples, and bananas), some people like bananas more than apples more than coconuts, or apples more than bananas more than coconuts, or coconuts more than apples more than bananas! and that's just value comparisons, the values of the "tastiness" of the fruits could be vastly different, not to mention there isn't really a specific way to measure the tastivolts of each fruit for each person.

[gold stinger]

tl;dr of Frank's Post:

for all the people saying 17:
the bananas in the final equation are missing a banana each, and there's only 1 half of a coconut.

for all the people saying 14.5:
the apple in apple + banana + banana = 18 doesn't have a leaf like the rest of the apples

for all the people saying 14, 15, or 9:
how? You probably messed up on banana counting, coconut counting, or apple leaf counting somewhere.

edit:
here is answer:

A+A+A=30
30/3 = 10
A = 10
-------------------
a+B+B=18
-------------------
B-C=1
-------------------
(C/2)+A+((B/4)*3) = ??
(C/2)+10+((B/4)*3)

No one can find the answer to a, meaning you can't solve for B
and because you can't solve for B, you can't solve for C.
The only thing that you can solve is A.