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#41 |
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Resident Penguin
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uh.... (n+1) + (n+1) doesn't equal m(n+1), if m is (n+1). That's like saying (n+1)(n+1) = (n+1) + (n+1).
and you can't divide by zero (a-b) in the first one. |
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#42 |
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FFR Player
Join Date: Apr 2005
Posts: 9
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re flash stinger - good luck with "getting my info." Does anyone want my IP? What would one do, exactly? All of my important documents are encrypted and backed up on athena.
Word on the street is that hacking is dead. BTW: MIT's root pwd is public -> You can ssh remotely and use neo to find all a person's information if you have any other bit of their information... Hacking people at MIT isn't hard, it's just not done because it's poor form/immature. --- Actually, someone used the root login to install a fake login screen on public workstations recently and harvested a bunch of email addresses. Too bad they got caught and their asses are getting expelled. *shrug* -Bigsley |
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#43 | ||
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FFR Player
Join Date: Apr 2005
Posts: 49
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Quote:
(n+1)(n+1) = m(n+1) and yes, that is the response, i divided by 0 in both. Dividing by zero leads to some pretty interesting results, eh? This shows you why it's important to observe rules about domain restrictions, or you can come up with all kinds of mayhem. (i.e. [a-b] and [n+1-m] both equal 0). I'm glad there are some smart people out there. Some people on other forums believed me and had to ask for why it works. Quote:
FYI, "Hacking" isn't dead. Cracking is on the drop, but most "hacks" are not reported, and are hardly ever harmful. Learn the lingo. Unfortunately, there will always be script kiddies attacking server's and games, just for fun. Hey, I have done it, but thinking that hacking is "dead" is simply stupid. |
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#44 |
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FFR Player
Join Date: Apr 2005
Posts: 9
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eh.
I may be stupid, but I'm still not really very worried. To the best of my knowledge, the following are true: 1) The russian mafia probably has all of my identifying information (ssn, credit card #, etc.) 2) I don't really have anything for anyone to steal. I don't have much money and if someone wanted it I would probably give it to them (assuming they had at least a coherent reason). If they want my few hundred dollars to buy a watch or something then that's just dumb. -Bigsley |
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#45 |
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FFR Player
Join Date: Apr 2005
Posts: 49
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true, Hacking is mostly done to small online buisnesses, who eventually fix the problem. So crackers inevitably help the world!!!! not really, but w/e
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w/e |
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#46 |
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FFR Player
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FlashStinger should be banned from CT
MIT was too depressing and brick and scary, so I didn't go there.. I also loved how sterotypical it was that a white man and an asian woman were having a jewish wedding outside when I went to visit it back in the day
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but for now... postCount++
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#47 |
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FFR Player
Join Date: Apr 2005
Posts: 49
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I should be banned from CT? on what grounds......
I am not claiming to be a hacker or cracker of any sorts and sorry if i stepped on your toes about some things, but as I recall this is a forum based on thinking critically and I have thought about my comments. I also in no way claim to be in any way smarter than a man or woman who can get into MIT. Heck, I'm just a highschool student in a school possibly losing it's acreditation so don't take many of my responses on Calc III that seriously. Sure I understand e^(i*π) but that doesn't mean much.
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w/e |
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#48 |
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FFR Player
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I think what bigsleytheoaf was referring to are "wannabes". However, I don't think that was appropiate for this thread bigsley. I think everyone in here was just excited about what they know and felt good about it, especially since many who did are quite young. I can see your point, but it wasn't needed for this thread.
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#49 |
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FFR Player
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Since I'm insane enough to return to the original purpose of this thread, I'll offer an alternative "proof." (Note that y' = dy/dx).
y = cos(x) + isin(x) y' = -sin(x) + icos(x) y' = i(isin(x) + cos(x)) y' = iy y'/y = i ln(y) = ix y = e^(ix) e^(ix) = cos(x) + isin(x) Plug in pi for x and you get your little -1 bit. *Hopes that anyone who knows better will conveniently ignore my exclusion of an integration constant.* |
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#50 |
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FFR Player
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ok, I'd just like to make the point that bigsley (1) posted all about his MIT math major in one of his first 9 posts (2) is a member of FFR (3) is a MATH MAJOR (4) brags about this on the internet.
I'm willing to bet that at least one of the following is true. - his rich parents pay for his amazing education - he lacks social skills - he's arrogant in real life too, though too timid to show it outwardly (which, admittedly, is probably a good thing) - is arguing for the sake of being different |
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