Go Back   Flash Flash Revolution: Community Forums > General Discussion > Chit Chat
Register FAQ Community Calendar Today's Posts Search

Reply
 
Thread Tools Display Modes
Old 01-19-2011, 07:36 PM   #1
Organist
FFR Player
 
Organist's Avatar
 
Join Date: Mar 2009
Posts: 26
Default I need help with calculus homework

I have just a couple questions regarding integrals

first question:

if I'm taking the integral of something like:

∫x^5dx would it equal x^6/6+c without the integral sign? or is the integral sign included

second question: I need help finding the integral of functions that include fractional exponents like:

∫8^t 2/3 dt

= 8∫t^2/3dt
= (8^t5/3)/5/3 +c (because I added one to the exponent)

but I get stuck here.. what do I do after this? multiply by it's recipriol? I'm not sure how to do that

Last question:

is it true that:

∫1/xdx = natural log of the absolute value of x plus your constant?

I want to make sure I did this problem correctly:

∫9/u du
= 9∫1/u du
= 9ln lul + c?

or is this wrong?

thx
Organist is offline   Reply With Quote
Old 01-19-2011, 07:41 PM   #2
Tidus810
slimy, yet ... satisfying
FFR Simfile AuthorFFR Veteran
 
Tidus810's Avatar
 
Join Date: May 2007
Age: 28
Posts: 1,244
Default Re: I need help with calculus homework

Preeetty sure everything you did there was correct, haha.
1 - no integral sign, that's all.
2 - is it 8^t2/3 or 8(t^2/3)? If it's the second, then the solved integral is just 8(3/5)t^5/3, or 24t^5/3 all over 5.
3 - correct.

Hope that helps, even though you don't look like ya needed it. :P

Last edited by Tidus810; 01-19-2011 at 07:43 PM..
Tidus810 is offline   Reply With Quote
Old 01-19-2011, 07:46 PM   #3
Reincarnate
x'); DROP TABLE FFR;--
Sectional ModeratorFFR Veteran
 
Reincarnate's Avatar
 
Join Date: Nov 2010
Posts: 6,334
Default Re: I need help with calculus homework

1. Without
2. Assuming you ask for the integral of 8(t^2/3), it'd be like 8 * the integral of t^2/3. Increasing the exponent here by 1 is the same as increasing it by 3/3, so (t^(5/3))/(5/3). Multiply by the 8 you moved out and you get (24/5)t^(5/3) + C
3. The integral of 1/x dx is ln(x)+C. So the integral of 9/u du is simply 9*ln(u) + C


EDIT: Watch out Tidus -- you divide by the raised exponent, not multiply

Last edited by Reincarnate; 01-19-2011 at 07:48 PM..
Reincarnate is offline   Reply With Quote
Old 01-19-2011, 07:52 PM   #4
Organist
FFR Player
 
Organist's Avatar
 
Join Date: Mar 2009
Posts: 26
Default Re: I need help with calculus homework

perfect thanks guys
Organist is offline   Reply With Quote
Reply


Currently Active Users Viewing This Thread: 1 (0 members and 1 guests)
 

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump



All times are GMT -5. The time now is 11:53 PM.


Powered by vBulletin® Version 3.8.1
Copyright ©2000 - 2021, Jelsoft Enterprises Ltd.
Copyright FlashFlashRevolution