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#1 | |
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Abraxas Hydroplane
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So I'm playing Neverwinter Nights 2, and there's this riddle. It's answer should be a three digit number, but I can't seem to find it. (I have tried gamefaqs but the puzzle is randomized so there is no definite answer,)
9 are we when taken all 3. Last one slain than six remain. None survive, our first less five. I've tried but I can't seem to find it. Thanks!
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#2 |
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FFR Veteran
Join Date: Jan 2007
Posts: 1,496
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513
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#3 |
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Zageron E. Tazaterra
Infrastructure & Game
Join Date: Apr 2007
Location: British Columbia, Canada
Posts: 6,463
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Answer = xyz in one number no multiplication.
x + y + z = 9 x + y - z = 6 x = -5 Try that. :S
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Praise the sun mofo
Join Date: Sep 2005
Location: Lordran
Age: 28
Posts: 4,177
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the answer is va-gina
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#5 | ||
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Abraxas Hydroplane
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I'll try it along with a lot of other answers when I get them.
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#6 |
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Zageron E. Tazaterra
Infrastructure & Game
Join Date: Apr 2007
Location: British Columbia, Canada
Posts: 6,463
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Your supposed to use that formula / system of equations to figure it out. Fine I'll do it.
Edit: It was wrong anyways, I think bballa48 is right.
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Last edited by Zageron; 09-30-2008 at 09:30 PM.. |
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#7 | ||
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Abraxas Hydroplane
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EDIT: I'm trying to solve it but I am stuck. Ugh. EDIT2: Oh well it turns out it's unsolvable. If x is = to -5 you still get a negative number in there.
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Last edited by MooMoo_Cowfreak; 09-30-2008 at 09:38 PM.. |
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#8 |
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Professor Spellcheck
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I can only come up with 423 ,333 ,243 ,153 , or 063. You can use zeros, right?
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#9 |
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FFR Player
Join Date: Mar 2007
Posts: 41
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6 (9) 5 (8) 0 (3) [4]
650 983 984 etc. I don't know if I'm right or wrong... |
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#10 |
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FFR Player
Join Date: Dec 1969
Location: New York City, New York
Posts: 8,023
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a+b+c=9
a+b=6 a-5=0 a=5, so b=1 and c=3 try 513 |
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#11 |
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Zageron E. Tazaterra
Infrastructure & Game
Join Date: Apr 2007
Location: British Columbia, Canada
Posts: 6,463
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This is what my equation was aiming for, but I messed it up D:
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