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#1 |
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FFR Player
Join Date: Aug 2005
Posts: 218
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They're both pretty similar so help with either one would be fine. No idea at all how to do these.. =/
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Last edited by DarkVampiress21; 02-10-2008 at 09:46 PM.. |
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#2 |
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FFR Simfile Author
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If this is completely wrong, someone please say so.
The depth will be the smallest dimension, yes? So I would let d be the depth of the compartment. The volume should then be: d(d+1)(d+3) = 8 If my math is right, that simplifies to d^3 + 4d^2 + 3d - 8 = 0. Notice that the left side is also equal to zero when d = 1. So you can use synthetic division with (d - 1) as the divisor. Edit: Now that I read it again, they probably wanted the volume equation in terms of the width. The equation changes, but you use (w - 2) as a divisor, and get the same dimensions in the end. Last edited by MeaCulpa; 02-10-2008 at 11:30 PM.. |
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#3 |
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FFR Player
Join Date: Aug 2005
Posts: 218
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Hmm... Well, I just wrote what you said, but pretty much made stuff up on whatever I didn't understand. Thanks anyway. =)
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