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#5 |
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FFR Player
Join Date: Jul 2007
Location: toronto
Posts: 38
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Thanks a lot buddy I got it. Let me post my work in a second for you to look over
2x log 3 - log 3^6x = -log 9 2x log 3 - 6xlog 3 = - log 9 2x (log 3 - 3log 3) = -log 9 2x (log 3/9) = - log 9 2x = - log 9 / log 1/3 2x = 2 x = 1 =) Thanks for the help flipsta_lombax and Jtehanonymous. Last edited by og4lif; 01-19-2008 at 10:16 PM.. |
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