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#11 |
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FFR Player
Join Date: Dec 1969
Location: New York City, New York
Posts: 8,340
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Nope, *all* independent variables here. The system operation only depends on the number of working parts, so therefore you need some crazy combinatorics to accurately determine what that independent probability is given by how many parts are being used. The answer changes depending on the requirement for functionality as well as k.
If you want to know my solution, let me know if anyone cares enough, rofl. |
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