12-3-2011, 12:33 AM | #1 |
FFR Veteran
Join Date: Feb 2006
Location: in your worst nightmere
Posts: 555
|
Equations
Forgot how many numbers I was using, but I challenge accepted my dad a long time ago, yeah cool childhood, I know.
Use numbers 1-9 and make an equation with any symbol you like in math or even combine them, try keeping it algebra, and make the answer = 1,2,3,4....as far as it goes. Use all 1-9. Hard to explain, goes a little like this. List as many as you like, or just list a seemingly hard/impossible number to get. Try not listing pointless numbers like 1233312312312445516351351234234. 1=9-8+7-6+5-4-3+2-1 2=(9-8+7-6+5-4-3+2)1 100=(9+1)(3+7)(6-5)+8-(4x2)
__________________
Reminder for self to make new sig. Last edited by Renevatia; 12-3-2011 at 12:38 AM.. |
12-3-2011, 12:39 AM | #2 |
D6 FFR Legacy Player
Join Date: Jan 2009
Age: 33
Posts: 4,342
|
Re: Equations
3=(9-8+7-6+5-4-3+2)+1
xd |
12-3-2011, 12:43 AM | #3 |
The Doctor
Join Date: Apr 2006
Age: 35
Posts: 6,145
|
Re: Equations
3=9-8+7-6+5-4-3+2+1
4=(9+8+7-6-5-4-3-2)1 5=9+8+7-6-5-4-3-2+1 6=(9+8-7-6+5-4-3+1)*2 Edit:// 7=9+8-7-6-5+4+3+2-1 8=(9+8-7-6-5+4+3+2)1 9=9+8+7-6-5-4+3-2-1 Edit2:// 1=1^2^3^4^5^6^7^8^9 =p Last edited by TheSaxRunner05; 12-3-2011 at 01:01 AM.. |
12-3-2011, 12:49 AM | #4 |
Kawaii Desu Ne?
Join Date: Dec 2007
Location: The Kawaiian Island~
Age: 30
Posts: 4,182
|
Re: Equations
10 = 9 + 1 + dₓ(8) + dₓ(7) + dₓ(6) + dₓ(5) + dₓ(4) + dₓ(3) + dₓ(2)
Last edited by reuben_tate; 12-3-2011 at 12:59 AM.. |
12-3-2011, 12:57 AM | #5 |
The Doctor
Join Date: Apr 2006
Age: 35
Posts: 6,145
|
Re: Equations
168,781,726= Sq Root(9)^8 * Sq Root(7)^6 * Sq Root(5)^4 * Sq Root(3)^2 +1
Cant believe that made a whole number lol |
12-3-2011, 01:00 AM | #6 |
FFR Player
Join Date: Apr 2011
Posts: 35
|
Re: Equations
They are all raised to even powers, so there aren't really any ugly decimals caused by the square roots: that equation is basically 9^4 + 7^3 + 5^2 + 3 + 1
|
12-3-2011, 01:01 AM | #7 | |
The Doctor
Join Date: Apr 2006
Age: 35
Posts: 6,145
|
Re: Equations
Quote:
Edit:// 0=(-1)9+8+7-6+5-4-3+2 Last edited by TheSaxRunner05; 12-3-2011 at 01:14 AM.. |
|
12-3-2011, 01:08 AM | #8 |
Kawaii Desu Ne?
Join Date: Dec 2007
Location: The Kawaiian Island~
Age: 30
Posts: 4,182
|
Re: Equations
11 = 6+5+9-8+1-2+7-4-3
Maybe that's why the OP said Algebra only. If not, I could just spawn as many " + 1"s into the equation by adding "+ dₓ(x)." lmfao |
12-3-2011, 01:20 AM | #9 |
FFR Veteran
Join Date: Feb 2006
Location: in your worst nightmere
Posts: 555
|
Re: Equations
1337= 1327+4+9-5+8-6
9001= 9251-((6-9+8)^3)x sqrt(4) 2012= [563-(2+8)(7-1)]4
__________________
Reminder for self to make new sig. Last edited by Renevatia; 12-3-2011 at 01:35 AM.. |
12-3-2011, 01:24 AM | #10 |
The Doctor
Join Date: Apr 2006
Age: 35
Posts: 6,145
|
Re: Equations
11= 9 + (Sin(8+5)^2 + Cos(7+6)^2) + (Sin(4+1)^2 + Cos(3+2)^2)
Does squaring count as a digit, or can we square as much as we want? |
12-3-2011, 01:28 AM | #11 |
FFR Veteran
Join Date: Feb 2006
Location: in your worst nightmere
Posts: 555
|
Re: Equations
well yes, you can argue that if by that logic sqrt should be counted ^(1/2) but theres a symbol (without numbers shown)for sqrt but no symbol for squares.
__________________
Reminder for self to make new sig. |
12-3-2011, 01:32 AM | #12 |
The Doctor
Join Date: Apr 2006
Age: 35
Posts: 6,145
|
Re: Equations
Gah, I was trying to get 1337 legit but I got ...
1335 = (9*8*7*6/4)*(3/2)+1 |
12-3-2011, 01:40 AM | #13 | |
FFR Veteran
Join Date: Feb 2006
Location: in your worst nightmere
Posts: 555
|
Re: Equations
Quote:
1000000= (2^((sqrt(9))!!/3!))-485768*1 , someone try to do this legit too lol.
__________________
Reminder for self to make new sig. Last edited by Renevatia; 12-3-2011 at 01:50 AM.. |
|
12-3-2011, 01:52 AM | #14 |
The Doctor
Join Date: Apr 2006
Age: 35
Posts: 6,145
|
Re: Equations
Got it, I found out working backwards is so much easier
1337 = ((1*(4+5+6)-8)*3*9+2)*7 Edit:// Yea work backwards 1,000,000 = 5^6*1(8*7+9+4-3-2) Edit2:// 5^6 is gold for these multiples of 1,000,000 .... 10,000,000 = 5^6*8*(3^4-1)+(9-7-2) Edit3:// Gah, I almost got my number of games played, too bad the 65* is cheating 21733 = (65*(7/2)*8-9)(3*4)+1 Edit4:// Nvm, got it! Games played 21,733 = ((6+7*(7/2)*8*5-9)*3*4+1 Last edited by TheSaxRunner05; 12-3-2011 at 03:01 AM.. |
12-3-2011, 03:22 AM | #15 | |
FFR Veteran
Join Date: Feb 2006
Location: in your worst nightmere
Posts: 555
|
Re: Equations
Quote:
Try your total score lolol. 8533539750
__________________
Reminder for self to make new sig. |
|
12-3-2011, 05:11 AM | #16 |
Kawaii Desu Ne?
Join Date: Dec 2007
Location: The Kawaiian Island~
Age: 30
Posts: 4,182
|
Re: Equations
100,000,000 = (5^6)*(4^3)*[(9+1)^2]*(8-7)
EDIT 1: 1,000,000,000 = (5^6)*(4^3)*[(9+1)^(2+8-7)] EDIT 2:10,000,000,000 = (5^6)*(4^3)*(9+1)^[((8!)/(7!))/2] EDIT 3: 100,000,000,000 = (5^6)*(4^3)*{(9+1)^(7-[sqrt(8)/sqrt(2)])} EDIT 4: 1,000,000,000,000 = (5^6)*(4^3)*{(9+1)^[((8!)/(7!))-2]} EDIT 5: 10,000,000,000,000 = (5^6)*(4^3)*(9+1)^((7!)/((8-2)!)) EDIT 6: 100,000,000,000,000 = (5^6)*(4^3)*(8+2)^((9-1)!/(7!)) EDIT 7: 1,000,000,000,000,000 = (5^6)*(4^3)*(9+1)^(sqrt(8)/sqrt(2)+7) EDIT: Thanks for the 5^6 trick Sax! ^_^ EDIT: I have too much time on my hands right now ._. Last edited by reuben_tate; 12-3-2011 at 05:59 AM.. |
12-7-2011, 11:53 AM | #17 |
XFD
Join Date: Mar 2008
Location: Connecticut
Age: 33
Posts: 4,924
|
Re: Equations
equations are a tool overall used as a method to find a particular answer.....
Here's an example I had for a question on my "calc III" test.... too vague for me to answer I wanna see what you guys come up with.... Find a symmetrical graph going through the points P(1,2,4) and P(3,4,5 how would YOU guys find the "answer" to "that question" (specifically it was a test written on paper so I'd have to answer with respect to a "cartesian coordinate plane") (x,y)
__________________
I bring my math homework to church. It helps me find a higher power. Dennis, Nell, Edna, Leon, Nedra, Anita, Rolf, Nora, Alice, Carol, Leo, Jane, Reed, Dena, Dale, Basil, Rae, Penny, Lana, Dave, Denny, Lena, Ida, Bernadette, Ben, Ray, Lila, Nina, Jo, Ira, Mara, Sara, Mario, Jan, Ina, Lily, Arne, Bette, Dan, Reba, Diane, Lynn, Ed, Eva, Dana, Lynne, Pearl, Isabel, Ada, Ned, Dee, Rena, Joel, Lora, Cecil, Aaron, Flora, Tina, Arden, Noel, and Ellen sinned. Last edited by iCeCuBEz v2; 12-7-2011 at 12:22 PM.. |
12-7-2011, 01:24 PM | #18 |
stepmania archaeologist
Join Date: Aug 2005
Age: 34
Posts: 4,090
|
Re: Equations
What does it mean by "symmetrical"? I mean, I'd consider planes and lines to have symmetry, so any plane going through those two points (e.g. z=(x+7)/2) seems to work.
PS: Here's a fun one: 123456789 = ((7+3)^(8+sqrt(4))-1)/(9^2)-6+5
__________________
Best AAA: Policy In The Sky [Oni] (81) Best SDG: PANTS (86) Best FC: Future Invasion (93) Last edited by qqwref; 12-7-2011 at 04:13 PM.. |
12-7-2011, 02:31 PM | #19 |
XFD
Join Date: Mar 2008
Location: Connecticut
Age: 33
Posts: 4,924
|
Re: Equations
yah ok you're confused as well..... I could've made any "graph" I wanted but it was wayyyy to general with its definition of "symmetrical"
It could've had translational symmetry...... symmetry with respect to x-axis..... with respect to y-axis..... rotational symmetry...... across that particular plane in which those points intersect...... I really had no ****ing idea how to answer this question...... If I made a circle on a cartesian coordinate plane.... how would I figure out the radius.....??? I "could" take those two points and create a function that could be written as "symmetrical" across the y-axis.... which would appear as a quadratic function or maybe even a quartic function or something asinine like that..... but was I given enough "information" to conceptualize this problem to a particular formula (or function as what it was defined as in this question.....) this little information could be manipulated into so many "cartesian functions"....... ugh Wait: I think I got it now..... If I find the distance between those 2 points in the 3 dimensional coordinate plane..... that new found line will create a plane that it is sitting upon.... so I can just use distance formula between those 2 points and then THAT is the radius??? (if i want to graph a circle on a cartesian coordinate plane)
__________________
I bring my math homework to church. It helps me find a higher power. Dennis, Nell, Edna, Leon, Nedra, Anita, Rolf, Nora, Alice, Carol, Leo, Jane, Reed, Dena, Dale, Basil, Rae, Penny, Lana, Dave, Denny, Lena, Ida, Bernadette, Ben, Ray, Lila, Nina, Jo, Ira, Mara, Sara, Mario, Jan, Ina, Lily, Arne, Bette, Dan, Reba, Diane, Lynn, Ed, Eva, Dana, Lynne, Pearl, Isabel, Ada, Ned, Dee, Rena, Joel, Lora, Cecil, Aaron, Flora, Tina, Arden, Noel, and Ellen sinned. Last edited by iCeCuBEz v2; 12-7-2011 at 02:36 PM.. |
12-7-2011, 04:15 PM | #20 |
stepmania archaeologist
Join Date: Aug 2005
Age: 34
Posts: 4,090
|
Re: Equations
If you create a circle (or sphere!) so that the two points are exactly opposite each other on the curve, the radius will be half of the distance between those points (and the center will be the midpoint of the two points). This is getting a bit off-topic, though
__________________
Best AAA: Policy In The Sky [Oni] (81) Best SDG: PANTS (86) Best FC: Future Invasion (93) |
Currently Active Users Viewing This Thread: 1 (0 members and 1 guests) | |
|
|