Math problem for credits!!

leo172519 · 11-7-2007, 04:58 PM

So I've been trying to help my gf with her math problem but i honestly cannot figure out a possible solution. I decided against putting this in CT because honestly there is no real discussion. Really looking for some help on this if anyone would like to give it a go. Its technically a trig problem, but I apparently cannot come to an answer thats not imaginary.

Heres the equation...

log8(3x^2 - 35.33x + 2622616.88)^.5 = 3

note: that's log base 8.

I used a calculator online and got 7/3 2.66667, but no clue how it got to there.

Thanks to whoever gets it, ill give like 1000 credits if i get an answer soon

ice_dragon9477 · 11-7-2007, 05:23 PM

looks like a fun problem

but i suck so much at math that i dont even knw what the question is asking for

i used to be good at it when the questions were in the form of 1 + 1 = ? but after that...

sorry cant help

leo172519 · 11-7-2007, 05:26 PM

lol i know what you mean :P

**foilman8805** · 11-7-2007, 05:27 PM

eh. Rubix is here. he'll answer it.

**knuckles2224** · 11-7-2007, 05:42 PM

lol what?

bluguerrilla · 11-7-2007, 05:46 PM

Just solve 8^[log8(3x^2 - 35.33x + 2622616.88)^.5] = 8^3 since it's equivalent to what you have up there.

since n^log_n(z) = z it becomes an easy quadratic. Yay!

P.S. You could even use the log_n(z^(1/2))= 1/2 log_n(z) property first if you like.

Edit: Is that enough of a hint for you?

bomberboi200 · 11-7-2007, 05:49 PM

MrRubix · 11-7-2007, 05:53 PM

blu: Only problem is that log(x^.5) is not the same as log(x)^.5. For instance, .5*log(5) is the same as log(5^.5) but log(5)^.5 is not the same as .5*log(5)

log8(3x^2 - 35.33x + 2622616.88)^.5 = 3
log8(3x^2 - 35.33x + 2622616.88) = 9
3x^2 - 35.33x + 2622616.88 = 8^9 = 134217728
3x^2 - 35.33x - 131595111 = 0
Now we have ourselves a pretty little quadratic.

a = 3, b = -35.33, c = -131595111

(-b +/- (b^2-4ac)^.5)/2a

Let's start with the first solution (using +)
(-(-35.33) + ((-35.33)^2-4*(3)*(-131595111))^.5)/(2*3) = 6628.9595
Second solution (using -)
(-(-35.33) - ((-35.33)^2-4*(3)*(-131595111))^.5)/(2*3) = -6617.18283

So x can be 6628.9595 or -6617.18283

I haven't done logs in a while but I think this is correct. Anyone who can verify would be more than welcome, lol. It's possible I botched it somewhere.

CREDZ PLZ.

bluguerrilla · 11-7-2007, 05:59 PM

Whatever, I assumed he could do the 'simple' stuff. You did pretty much what I told him to do.

I don't solve problems for people, I do enough of that on my own.

Also, like you care about the credits, lol.

MrRubix · 11-7-2007, 06:00 PM

I'm gonna be low after my tourney's over -- so I actually could use the credits.

**csoup1414** · 11-7-2007, 06:08 PM

wow, i seriously wish i could help
i am really good at math, but i am only in algebra 2, so yeah
trig next year tho whoo!

MarukuAntoni · 11-7-2007, 06:08 PM

dam! i forgot how to do these problems. thats what 1 year away from a math class can do to me.

leo172519 · 11-7-2007, 08:35 PM

lol thanks rubix i didnt even think about squaring both sides first

looks like you win!

EDIT: I tried the way you stated Blu from the start, i just didnt write it out for...some reason...i sent you 100 creds for the help

ty

xinpig · 11-7-2007, 08:46 PM

posts 6 and 8 lol i dont get any of it

**25thhour** · 11-7-2007, 09:09 PM

Lmao i'm only a grade 8 student. =D Hard ****.

omgitznpv · 11-7-2007, 09:25 PM

lol, I actually understand what Rubix is doing.

and I'm only 13.

**koga939** · 11-7-2007, 09:38 PM

Sorry. DUNNO.

-My Overall FFR stats-

Stats: Crappy
Rank: 2493
Grand Total: 1135822870
Average Rank: 29000 something
MP Level: 9 and a half
Member Since: 8-26-2006
AAAs: 3 (Free Space, Excite Bike, Spontaneous Hydroxide, Disconnected (dont count))
Best AAA: Spontaneou Hydroxide
FCs: 30 (Dont know all of them.)
Best FC: CIA Rave
Overall: I suck

**Nyokou** · 11-7-2007, 09:39 PM

You're asian, omgitznpv.

Verruckter · 11-7-2007, 09:40 PM

Quote:

Originally Posted by koga939

Sorry. DUNNO.

-My Overall FFR stats-

Stats: Crappy
Rank: 2493
Grand Total: 1135822870
Average Rank: 29000 something
MP Level: 9 and a half
Member Since: 8-26-2006
AAAs: 3 (Free Space, Excite Bike, Spontaneous Hydroxide, Disconnected (dont count))
Best AAA: Spontaneou Hydroxide
FCs: 30 (Dont know all of them.)
Best FC: CIA Rave
Overall: I suck

We totally care about your overall stats

**koga939** · 11-7-2007, 09:44 PM

Quote:

Originally Posted by Verruckter

We totally care about your overall stats

True, true. But scine I have no life, I decide to be random for a living. Its my hobby. Im a total faliure.

11-7-2007, 04:58 PM	#1
leo172519 4 year veteran Join Date: Apr 2004 Location: by PA and WV Posts: 176	Math problem for credits!! So I've been trying to help my gf with her math problem but i honestly cannot figure out a possible solution. I decided against putting this in CT because honestly there is no real discussion. Really looking for some help on this if anyone would like to give it a go. Its technically a trig problem, but I apparently cannot come to an answer thats not imaginary. Heres the equation... log8(3x^2 - 35.33x + 2622616.88)^.5 = 3 note: that's log base 8. I used a calculator online and got 7/3 2.66667, but no clue how it got to there. Thanks to whoever gets it, ill give like 1000 credits if i get an answer soon __________________ AAA #: 106 Best AAA: Mute City Remix Greatest FC(s): Coat Czech, Strangeprogram, None Would Escape

11-7-2007, 05:23 PM	#2
ice_dragon9477 FFR Player Join Date: Feb 2005 Posts: 147	Re: Math problem for credits!! looks like a fun problem but i suck so much at math that i dont even knw what the question is asking for i used to be good at it when the questions were in the form of 1 + 1 = ? but after that... sorry cant help __________________

11-7-2007, 05:26 PM	#3
leo172519 4 year veteran Join Date: Apr 2004 Location: by PA and WV Posts: 176	Re: Math problem for credits!! lol i know what you mean :P __________________ AAA #: 106 Best AAA: Mute City Remix Greatest FC(s): Coat Czech, Strangeprogram, None Would Escape

11-7-2007, 05:27 PM	#4
foilman8805 smoke wheat hail satin Join Date: Sep 2006 Location: LA baby Age: 36 Posts: 5,704	Re: Math problem for credits!! eh. Rubix is here. he'll answer it.

11-7-2007, 05:46 PM	#6
bluguerrilla FFR Player Join Date: Apr 2006 Age: 41 Posts: 3,966	Re: Math problem for credits!! Just solve 8^[log8(3x^2 - 35.33x + 2622616.88)^.5] = 8^3 since it's equivalent to what you have up there. since n^log_n(z) = z it becomes an easy quadratic. Yay! P.S. You could even use the log_n(z^(1/2))= 1/2 log_n(z) property first if you like. Edit: Is that enough of a hint for you? __________________ Last edited by bluguerrilla; 11-7-2007 at 05:49 PM.. Reason: Well? :)

11-7-2007, 05:49 PM	#7
bomberboi200 FFR Player Join Date: Jul 2007 Posts: 385	Re: Math problem for credits!! LOL

11-7-2007, 05:53 PM	#8
MrRubix FFR Player Join Date: Dec 1969 Location: New York City, New York Posts: 8,340	Re: Math problem for credits!! blu: Only problem is that log(x^.5) is not the same as log(x)^.5. For instance, .5log(5) is the same as log(5^.5) but log(5)^.5 is not the same as .5log(5) log8(3x^2 - 35.33x + 2622616.88)^.5 = 3 log8(3x^2 - 35.33x + 2622616.88) = 9 3x^2 - 35.33x + 2622616.88 = 8^9 = 134217728 3x^2 - 35.33x - 131595111 = 0 Now we have ourselves a pretty little quadratic. a = 3, b = -35.33, c = -131595111 (-b +/- (b^2-4ac)^.5)/2a Let's start with the first solution (using +) (-(-35.33) + ((-35.33)^2-4(3)(-131595111))^.5)/(23) = 6628.9595 Second solution (using -) (-(-35.33) - ((-35.33)^2-4(3)(-131595111))^.5)/(23) = -6617.18283 So x can be 6628.9595 or -6617.18283 I haven't done logs in a while but I think this is correct. Anyone who can verify would be more than welcome, lol. It's possible I botched it somewhere. CREDZ PLZ. Last edited by MrRubix; 11-8-2007 at 11:46 PM..

11-7-2007, 05:59 PM	#9
bluguerrilla FFR Player Join Date: Apr 2006 Age: 41 Posts: 3,966	Re: Math problem for credits!! Whatever, I assumed he could do the 'simple' stuff. You did pretty much what I told him to do. I don't solve problems for people, I do enough of that on my own. Also, like you care about the credits, lol. __________________

11-7-2007, 06:00 PM	#10
MrRubix FFR Player Join Date: Dec 1969 Location: New York City, New York Posts: 8,340	Re: Math problem for credits!! I'm gonna be low after my tourney's over -- so I actually could use the credits.

11-7-2007, 06:08 PM	#11
csoup1414 FFR Veteran Join Date: Jul 2006 Location: Pennsylvania Age: 32 Posts: 834	Re: Math problem for credits!! wow, i seriously wish i could help i am really good at math, but i am only in algebra 2, so yeah trig next year tho whoo! __________________

11-7-2007, 06:08 PM	#12
MarukuAntoni mmmMMMmmm Join Date: Apr 2007 Location: California Age: 36 Posts: 521	Re: Math problem for credits!! dam! i forgot how to do these problems. thats what 1 year away from a math class can do to me. __________________ IF I CAN CLIMB A TREE, I CAN CLIMB MT EVEREST. IF I CAN DRIVE A CAR, I CAN PILOT A SPACE SHUTTLE. IF I CAN PEE, I CAN BE THE PRESIDENT. IF I CAN POO, I CAN RULE THE WORLD!

11-7-2007, 08:35 PM	#13
leo172519 4 year veteran Join Date: Apr 2004 Location: by PA and WV Posts: 176	Re: Math problem for credits!! lol thanks rubix i didnt even think about squaring both sides first looks like you win! EDIT: I tried the way you stated Blu from the start, i just didnt write it out for...some reason...i sent you 100 creds for the help ty __________________ AAA #: 106 Best AAA: Mute City Remix Greatest FC(s): Coat Czech, Strangeprogram, None Would Escape Last edited by leo172519; 11-7-2007 at 08:43 PM..

11-7-2007, 08:46 PM	#14
xinpig FFR Player Join Date: Apr 2006 Location: At my Computer Age: 34 Posts: 1,072	Re: Math problem for credits!! posts 6 and 8 lol i dont get any of it __________________ PSEUDO SKILL TOKENS! FC'd Blooddrunk with AVMISSING!

11-7-2007, 09:09 PM	#15
25thhour *I like max* Join Date: Feb 2007 Location: Vancouver/Burnaby/East Van Age: 30 Posts: 2,921	Re: Math problem for credits!! Lmao i'm only a grade 8 student. =D Hard ****. __________________ r bae adam bae max bae bridget bae claudia bae trevor bae adam2 bae mayo bae keith bae

11-7-2007, 09:38 PM	#17
koga939 Tuturu! Join Date: Aug 2006 Location: Kansas City Age: 28 Posts: 185	Re: Math problem for credits!! Sorry. DUNNO. -My Overall FFR stats- Stats: Crappy Rank: 2493 Grand Total: 1135822870 Average Rank: 29000 something MP Level: 9 and a half Member Since: 8-26-2006 AAAs: 3 (Free Space, Excite Bike, Spontaneous Hydroxide, Disconnected (dont count)) Best AAA: Spontaneou Hydroxide FCs: 30 (Dont know all of them.) Best FC: CIA Rave Overall: I suck Last edited by koga939; 11-7-2007 at 09:40 PM..

11-7-2007, 09:39 PM	#18
Nyokou （￣ー￣） Join Date: Apr 2005 Location: United States Age: 32 Posts: 4,246	Re: Math problem for credits!! You're asian, omgitznpv. __________________ Twitter \| Instagram \| Snapchat: Nyokou

Currently Active Users Viewing This Thread: 1 (0 members and 1 guests)