MrRubix's Riddle Thread

[MrRubix_MK5]

In this thread, we will dedicate discussion to various riddles/puzzles/problems.

Next riddle:


Three men begin atop a mountain slope during a snowy night. Each man sits on top of their own flatbed cart on wheels (think Bugs Bunny cartoon, here). One of the men, Man #3, however, is stationed within a mountain tunnel, where no snow can pass through. Each man/cart is identical in every way, and their distances down to the bottom of the slope is the same. Each cart, at time 0, has no snow. They all start to go down the slope. Man #1 decides to sleep and does not do anything about the snow that falls onto his cart. Man #2 is constantly sweeping off snow that lands on his cart perpendicular to the direction of motion. Man #3, in the tunnel, obviously does nothing as he has no snow. Assume negligible friction, and assume no air drag or drag from midair snow -- all that matters here is the mass of any snow on the cart. Who makes it down to the bottom of the slope first, second, and third, and why?



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Shash, Soulstone, and Laggy are out in the woods chopping trees for wood for a campfire. Shash brings back 6 logs, while Soulstone brings back 4 logs. However, later that night, Laggy admits he didn't collect any wood. However, he has 10 coins he is willing to distribute between both Shash and Soulstone if they let him share in the campfire. How does he distribute the coins between the two in a fair and equitable way? (you have to explain your logic)

HINT: The answer is not 6 and 4 to Shash and Soulstone.


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Emerald, Fractal_Monkey, and Tass need to get to a location 30 miles away. Emerald and Fractal both walk at speeds of 3 mph each, but on a bike, they both go 5 mph. Tass can walk at 5 mph, but on a bike, he can go 15 mph. However, they only have one bike, and only one person can use the bike at any time. What is the shortest amount of time required to get all three of them to the location 30 miles away? What is your strategy?






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Here's one to get you started.

Imagine that the hour and minute hands of a clock are the same length. Imagine, also, that I am able to read the hands with 100% certainty (meaning I can tell EXACTLY how far the hour/minute hands have moved).

How many times exist over a 12 hour period where, if I were to look at the clock, I'd be unable to tell you what time it was?