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Old 08-4-2008, 11:00 AM   #21
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Default Re: MrRubix's Riddle Thread

Quote:
Originally Posted by MrRubix_MK5 View Post
Incorrect

If I said the hands looked like this:

|
|
|_____

What time would you tell me that is?
It can be one of two times...

12:15 or 3.00 ?
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Old 08-4-2008, 11:00 AM   #22
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Default Re: MrRubix's Riddle Thread

Quote:
Originally Posted by MrRubix_MK5 View Post
Incorrect

If I said the hands looked like this:

|
|
|_____

What time would you tell me that is?
I would say that it is 3 o clock.


Quote:
Originally Posted by wwwJ4mmYcouk View Post
It can be one of two times...

12:15 or 3.00 ?
If it was 12:15 then the top hand would be farther a long. Rubix you are correct.


EDITED: I was being stupid. *slaps head*
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Old 08-4-2008, 11:01 AM   #23
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Default Re: MrRubix's Riddle Thread

Quote:
Originally Posted by wwwJ4mmYcouk View Post
It can be one of two times...

12:15 or 3.00 ?
3:00 would be right.

12:15, not correct. Look at your watch when it's 12:15. Is the hour hand pointing straight up? When the minute hand makes a full rotation, does the hour hand suddenly "click" over one hour or does it move gradually with time?
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Old 08-4-2008, 11:02 AM   #24
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Default Re: MrRubix's Riddle Thread

It's only 3:00.

Code:
 |
|
---
This looks more like 12:15.

Edit: If 12 exact is 0 degrees, at 12:15 the hand would be at 90 degrees, but the hour would be at 7.5 degrees.
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Old 08-4-2008, 11:02 AM   #25
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Default Re: MrRubix's Riddle Thread

Yer i think i am out of my depth... Back to watching TV


EDIT: Rubix i understand about the hour hand being slightly more at an angle if it is 1/4 past the hour.
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Old 08-4-2008, 11:06 AM   #26
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Default Re: MrRubix's Riddle Thread

You can all use this to draw out your examples of time, not little slashs and things.

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Old 08-4-2008, 11:09 AM   #27
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Default Re: MrRubix's Riddle Thread

I'd rather just name angles because it gives exactness.
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Old 08-4-2008, 11:12 AM   #28
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Default Re: MrRubix's Riddle Thread

Incorrect

I am assuming your logic is overlaps minus noon, which is the "initial" answer most people would give at first glance
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Old 08-4-2008, 11:12 AM   #29
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Default Re: MrRubix's Riddle Thread

Oops, thought it was a different question the first time. My bad for not reading.

Okay, let m = number of degrees turned by the minute hand (mod 360)
h = number of degrees turned by the hour hand

now, h - m/12 = 0 (mod 30) is always true, so it follows that any time where the statement

m - h/12 = 0 (mod 30) (i)

is true would correspond to a pair of times where the hands can be interchanged.

Now, plugging some values of m and h into a table reveals that m-h/12 increases by 143 every 24 minutes i.e. m-h/12 increases at the rate of 143/24 per minute. The statement (i) holds true every 30*24/143 minutes, or every 5.034965 minutes.

Over a period of 12 hours (720 minutes), there are 143 times where (i) is true. One of these is 12:00, which can be discounted, so that leaves 142 times over 12 hours. For example, 12:05.034... is indistinguishable from 1:00.41958..., and so on.
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Old 08-4-2008, 11:28 AM   #30
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Default Re: MrRubix's Riddle Thread

You're in the right mindset, but, wrong
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Old 08-4-2008, 11:29 AM   #31
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Default Re: MrRubix's Riddle Thread

Rubix, I edited my post 500 times. Here it is.

http://www.flashflashrevolution.com/...8&postcount=19

P.S. ym barin hruts.
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Old 08-4-2008, 11:31 AM   #32
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Default Re: MrRubix's Riddle Thread

lol, no. There are times where you cannot tell.
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Old 08-4-2008, 11:33 AM   #33
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Default Re: MrRubix's Riddle Thread

I didn't say there weren't. You can't tell when it's at an 180 degree angle. you can't tell the difference between 12:31 and 6:01, 12:32 and 6:02, 12:33 and 6:03, etc.

Edit: yes you can. I suck at riddles. Leave me alone =(. This is a problem of hour to minute ratios and I'm bad at ratios. so bye.
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Old 08-4-2008, 12:09 PM   #34
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Default Re: MrRubix's Riddle Thread

12:00
1:05
2:10
3:15
4:20
5:25
6:30
7:35
8:40
9:45
10:50
11:55
12:00

All of these times are when the minute hand AND the hour hand are in the exact same position.

So, it's 13 if you count the last 12:00 and 12 if you don't.
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Old 08-4-2008, 12:14 PM   #35
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Default Re: MrRubix's Riddle Thread

Quote:
Originally Posted by hoochan View Post
12:00
1:05
2:10
3:15
4:20
5:25
6:30
7:35
8:40
9:45
10:50
11:55
12:00

All of these times are when the minute hand AND the hour hand are in the exact same position.

So, it's 13 if you count the last 12:00 and 12 if you don't.
These are the times he CAN tell us, I already did the same thing.

He wants to know what times he can't tell us.
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Old 08-4-2008, 12:17 PM   #36
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Default Re: MrRubix's Riddle Thread

12, because the minute hand would be directly over the hour hand once every hour, right?
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Old 08-4-2008, 12:19 PM   #37
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Default Re: MrRubix's Riddle Thread

12 is wrong.
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Old 08-4-2008, 12:19 PM   #38
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Default Re: MrRubix's Riddle Thread

Fine then *leaves*
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Old 08-4-2008, 12:21 PM   #39
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Default Re: MrRubix's Riddle Thread

Might be better if you try to explain, mathematically, when you would not be able to tell what time it was. And then use that framework to derive how many such times exist.
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Old 08-4-2008, 12:26 PM   #40
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Default Re: MrRubix's Riddle Thread

Oops...I read over the problem too quickly and assumed it was the more traditional coincidental problem (to which the answer has already been given). Yours is slightly more complex than it lends its appearance to. I'll get the solution after lunch. 8)
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