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#21 | |
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FFR Player
Join Date: Feb 2005
Location: England
Posts: 1,031
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Quote:
12:15 or 3.00 ?
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Frank Lee Morris Μήπως πραγματικά πνιγεί;
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#22 | |
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FFR Veteran
Join Date: Dec 2007
Location: Texas
Posts: 1,569
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Quote:
If it was 12:15 then the top hand would be farther a long. Rubix you are correct. EDITED: I was being stupid. *slaps head*
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Last edited by Beethovens mask; 08-4-2008 at 11:03 AM.. |
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#23 |
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Banned
Join Date: Jul 2008
Posts: 120
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3:00 would be right.
12:15, not correct. Look at your watch when it's 12:15. Is the hour hand pointing straight up? When the minute hand makes a full rotation, does the hour hand suddenly "click" over one hour or does it move gradually with time? |
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#24 |
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FFR Player
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It's only 3:00.
Code:
| | --- Edit: If 12 exact is 0 degrees, at 12:15 the hand would be at 90 degrees, but the hour would be at 7.5 degrees.
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I have a sig. Last edited by MahouMinachan; 08-4-2008 at 11:04 AM.. |
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#25 |
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FFR Player
Join Date: Feb 2005
Location: England
Posts: 1,031
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Yer i think i am out of my depth... Back to watching TV
![]() EDIT: Rubix i understand about the hour hand being slightly more at an angle if it is 1/4 past the hour.
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Frank Lee Morris Μήπως πραγματικά πνιγεί;
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#26 |
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FFR Veteran
Join Date: Dec 2007
Location: Texas
Posts: 1,569
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You can all use this to draw out your examples of time, not little slashs and things.
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#27 |
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FFR Player
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I'd rather just name angles because it gives exactness.
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I have a sig. |
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#28 |
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Banned
Join Date: Jul 2008
Posts: 120
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Incorrect
I am assuming your logic is overlaps minus noon, which is the "initial" answer most people would give at first glance |
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#29 |
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FFR Player
Join Date: Apr 2005
Location: Manchester, England
Posts: 464
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Oops, thought it was a different question the first time. My bad for not reading.
Okay, let m = number of degrees turned by the minute hand (mod 360) h = number of degrees turned by the hour hand now, h - m/12 = 0 (mod 30) is always true, so it follows that any time where the statement m - h/12 = 0 (mod 30) (i) is true would correspond to a pair of times where the hands can be interchanged. Now, plugging some values of m and h into a table reveals that m-h/12 increases by 143 every 24 minutes i.e. m-h/12 increases at the rate of 143/24 per minute. The statement (i) holds true every 30*24/143 minutes, or every 5.034965 minutes. Over a period of 12 hours (720 minutes), there are 143 times where (i) is true. One of these is 12:00, which can be discounted, so that leaves 142 times over 12 hours. For example, 12:05.034... is indistinguishable from 1:00.41958..., and so on. |
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#30 |
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Banned
Join Date: Jul 2008
Posts: 120
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You're in the right mindset, but, wrong
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#31 |
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Digital Dancing!
Join Date: Feb 2006
Location: 80 billion club, NE
Age: 33
Posts: 12,985
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Rubix, I edited my post 500 times. Here it is.
http://www.flashflashrevolution.com/...8&postcount=19 P.S. ym barin hruts.
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#32 |
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Banned
Join Date: Jul 2008
Posts: 120
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lol, no. There are times where you cannot tell.
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#33 |
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Digital Dancing!
Join Date: Feb 2006
Location: 80 billion club, NE
Age: 33
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I didn't say there weren't. You can't tell when it's at an 180 degree angle. you can't tell the difference between 12:31 and 6:01, 12:32 and 6:02, 12:33 and 6:03, etc.
Edit: yes you can. I suck at riddles. Leave me alone =(. This is a problem of hour to minute ratios and I'm bad at ratios. so bye.
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Last edited by rushyrulz; 08-4-2008 at 11:36 AM.. |
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#34 |
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woah shrooms
Join Date: Nov 2005
Posts: 3,838
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12:00
1:05 2:10 3:15 4:20 5:25 6:30 7:35 8:40 9:45 10:50 11:55 12:00 All of these times are when the minute hand AND the hour hand are in the exact same position. So, it's 13 if you count the last 12:00 and 12 if you don't. |
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#35 | |
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Massive flaming dildos.
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Quote:
He wants to know what times he can't tell us.
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#36 |
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FFR Veteran
Join Date: May 2008
Location: England, UK
Age: 34
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12, because the minute hand would be directly over the hour hand once every hour, right?
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#37 |
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Banned
Join Date: Jul 2008
Posts: 120
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12 is wrong.
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#38 |
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FFR Veteran
Join Date: May 2008
Location: England, UK
Age: 34
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Fine then *leaves*
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#39 |
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Banned
Join Date: Jul 2008
Posts: 120
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Might be better if you try to explain, mathematically, when you would not be able to tell what time it was. And then use that framework to derive how many such times exist.
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#40 |
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FFR Player
Join Date: Sep 2006
Location: it's a mystery oooo
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Oops...I read over the problem too quickly and assumed it was the more traditional coincidental problem (to which the answer has already been given). Yours is slightly more complex than it lends its appearance to. I'll get the solution after lunch. 8)
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