Patterns (For the math geeks)

archbishopjabber · 05-1-2007, 06:28 PM

The rules are simple. Post several numbers of a pattern you developed. The next member in line writes a formula that will result in the pattern, using x as the place in line of the number. For example, if the pattern was 2,4,6,8... the formula would be 2x. Always start the pattern off where x=1. Do not make them to overly complicated... at least in the beginning anyway. In order to post a pattern you must solve the last persons pattern correctly. Make sure your formula fits for all numbers they posted.

The first sequence:

1, 3, 6, 10, 15, 21, 28, 36, 45, 55...

**Doug31** · 05-1-2007, 06:31 PM

Triangular numbers, as in 1+2+3+...+n for the nth term.

Next sequence is
1, 2, 4, 8, 16, 32, 64, 128 (yea, really easy)

**brothaice** · 05-1-2007, 06:39 PM

y=2n

1, 3, 5, 7, 11, 13, 17, 19, 23...

I think all those are right.

**Doug31** · 05-1-2007, 06:43 PM

Are those supposed to be primes? If so, 2 should be on the list, and not 1.

Edit: and mine was NOT 2n, it was 2^n.

**Fantasticone** · 05-1-2007, 06:45 PM

+2

.3333, .1111, .0370, .0123, .0041

ledwix · 05-1-2007, 06:50 PM

^^^^^^^^^^
a(n) = (1)/(3^n)

new: 1, 4, 27, 256, 3125, 46656, 823543

**Doug31** · 05-1-2007, 06:52 PM

x^x

Next one is:
1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144...

**Fantasticone** · 05-1-2007, 06:53 PM

Add all previous numbers.

5000, 3125, 685.871, 76.293, 5.12

**Doug31** · 05-1-2007, 06:53 PM

It's not add ALL previous numbers, it's just adding the most recent 2.

**Fantasticone** · 05-1-2007, 07:10 PM

Quote:

Originally Posted by Fantasticone

Add all previous numbers.

5000, 3125, 685.871, 76.293, 5.12

Cough cough.

**brothaice** · 05-1-2007, 07:23 PM

Quote:

Originally Posted by Doug31

Triangular numbers, as in 1+2+3+...+n for the nth term.

Next sequence is
1, 2, 4, 8, 16, 32, 64, 128 (yea, really easy)

1 x 2 = 2

2 x 2 = 4

4 x 2 = 8

8 x 2 = 16

16 x 2 = 32

32 x 2 = 64

64 x 2 = 128

Let n represent the previous number in the sequence.

f(n)=2n

Doug or someone else please tell me how that is wrong.
Dont mean to bitch i just wanna know XD

EI_Tizzy · 05-1-2007, 07:27 PM

You are partly correct.

The equation for the NEXT term in this series is 2n, but the series as a whole is defined by 2^n.

Also, I have no clue on Fantasticone's one. My guess is that there is none XD

**Fantasticone** · 05-1-2007, 07:28 PM

500{1/(.n/n)}^n

**brothaice** · 05-1-2007, 07:30 PM

Quote:

Originally Posted by EI_Tizzy

You are partly correct.

The equation for the NEXT term in this series is 2n, but the series as a whole is defined by 2^n.

Also, I have no clue on Fantasticone's one. My guess is that there is none XD

Oh, i thought thats what we were finding, lol

**Doug31** · 05-1-2007, 07:37 PM

Quote:

Originally Posted by Fantasticone

500{1/(.n/n)}^n

That was too hard.

**Fantasticone** · 05-1-2007, 07:38 PM

Thought you were math geeks.

**Doug31** · 05-1-2007, 07:44 PM

It's so hard, I still don't get it. Wouldn't .n/n always equal 1/10? And then 1/(1/10) would always be 10, so it would just be 500*10^n? That doesn't work, but this isn't making sense to me lol.

**Fantasticone** · 05-1-2007, 07:48 PM

Oh **** I added extra brackets or whatever.

500(1/.n/n)^n

There we go.

**brothaice** · 05-1-2007, 08:05 PM

New pattern plz. I would write one, but its more fun figuring out you guys'.

**Fantasticone** · 05-1-2007, 08:13 PM

.0349, .0697, .1046, .1395

Im so evil.

05-1-2007, 06:28 PM	#1
archbishopjabber FFR Player Join Date: Dec 2005 Age: 81 Posts: 268	Patterns (For the math geeks) The rules are simple. Post several numbers of a pattern you developed. The next member in line writes a formula that will result in the pattern, using x as the place in line of the number. For example, if the pattern was 2,4,6,8... the formula would be 2x. Always start the pattern off where x=1. Do not make them to overly complicated... at least in the beginning anyway. In order to post a pattern you must solve the last persons pattern correctly. Make sure your formula fits for all numbers they posted. The first sequence: 1, 3, 6, 10, 15, 21, 28, 36, 45, 55...

05-1-2007, 06:31 PM	#2
Doug31 Falcon Paaaauuuunch!!!!!! Join Date: Jun 2004 Location: Washington Age: 38 Posts: 6,811	Re: Patterns (For the math geeks) Triangular numbers, as in 1+2+3+...+n for the nth term. Next sequence is 1, 2, 4, 8, 16, 32, 64, 128 (yea, really easy) __________________

05-1-2007, 06:39 PM	#3
brothaice FFR Simfile Author Join Date: Dec 2005 Age: 34 Posts: 2,940	Re: Patterns (For the math geeks) y=2n 1, 3, 5, 7, 11, 13, 17, 19, 23... I think all those are right.

05-1-2007, 06:43 PM	#4
Doug31 Falcon Paaaauuuunch!!!!!! Join Date: Jun 2004 Location: Washington Age: 38 Posts: 6,811	Re: Patterns (For the math geeks) Are those supposed to be primes? If so, 2 should be on the list, and not 1. Edit: and mine was NOT 2n, it was 2^n. __________________ Last edited by Doug31; 05-1-2007 at 06:53 PM..

05-1-2007, 06:45 PM	#5
Fantasticone D7 Elite Keymasher Join Date: Aug 2006 Age: 35 Posts: 6,003	Re: Patterns (For the math geeks) +2 .3333, .1111, .0370, .0123, .0041 __________________

05-1-2007, 06:50 PM	#6
ledwix Giant Pi Operator Join Date: Mar 2006 Location: California Age: 35 Posts: 2,878	Re: Patterns (For the math geeks) ^^^^^^^^^^ a(n) = (1)/(3^n) new: 1, 4, 27, 256, 3125, 46656, 823543

05-1-2007, 06:52 PM	#7
Doug31 Falcon Paaaauuuunch!!!!!! Join Date: Jun 2004 Location: Washington Age: 38 Posts: 6,811	Re: Patterns (For the math geeks) x^x Next one is: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144... __________________

05-1-2007, 06:53 PM	#8
Fantasticone D7 Elite Keymasher Join Date: Aug 2006 Age: 35 Posts: 6,003	Re: Patterns (For the math geeks) Add all previous numbers. 5000, 3125, 685.871, 76.293, 5.12 __________________ Last edited by Fantasticone; 05-1-2007 at 06:55 PM..

05-1-2007, 06:53 PM	#9
Doug31 Falcon Paaaauuuunch!!!!!! Join Date: Jun 2004 Location: Washington Age: 38 Posts: 6,811	Re: Patterns (For the math geeks) It's not add ALL previous numbers, it's just adding the most recent 2. __________________

05-1-2007, 07:28 PM	#13
Fantasticone D7 Elite Keymasher Join Date: Aug 2006 Age: 35 Posts: 6,003	Re: Patterns (For the math geeks) 500{1/(.n/n)}^n __________________

05-1-2007, 07:38 PM	#16
Fantasticone D7 Elite Keymasher Join Date: Aug 2006 Age: 35 Posts: 6,003	Re: Patterns (For the math geeks) Thought you were math geeks. __________________

05-1-2007, 07:44 PM	#17
Doug31 Falcon Paaaauuuunch!!!!!! Join Date: Jun 2004 Location: Washington Age: 38 Posts: 6,811	Re: Patterns (For the math geeks) It's so hard, I still don't get it. Wouldn't .n/n always equal 1/10? And then 1/(1/10) would always be 10, so it would just be 500*10^n? That doesn't work, but this isn't making sense to me lol. __________________

05-1-2007, 07:48 PM	#18
Fantasticone D7 Elite Keymasher Join Date: Aug 2006 Age: 35 Posts: 6,003	Re: Patterns (For the math geeks) Oh **** I added extra brackets or whatever. 500(1/.n/n)^n There we go. __________________

05-1-2007, 08:05 PM	#19
brothaice FFR Simfile Author Join Date: Dec 2005 Age: 34 Posts: 2,940	Re: Patterns (For the math geeks) New pattern plz. I would write one, but its more fun figuring out you guys'.

05-1-2007, 08:13 PM	#20
Fantasticone D7 Elite Keymasher Join Date: Aug 2006 Age: 35 Posts: 6,003	Re: Patterns (For the math geeks) .0349, .0697, .1046, .1395 Im so evil. __________________ Last edited by Fantasticone; 05-4-2007 at 10:11 PM..

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