|
|
|
|
#1 |
|
Banned
Join Date: Jul 2008
Posts: 120
|
In this thread, we will dedicate discussion to various riddles/puzzles/problems.
Next riddle: Three men begin atop a mountain slope during a snowy night. Each man sits on top of their own flatbed cart on wheels (think Bugs Bunny cartoon, here). One of the men, Man #3, however, is stationed within a mountain tunnel, where no snow can pass through. Each man/cart is identical in every way, and their distances down to the bottom of the slope is the same. Each cart, at time 0, has no snow. They all start to go down the slope. Man #1 decides to sleep and does not do anything about the snow that falls onto his cart. Man #2 is constantly sweeping off snow that lands on his cart perpendicular to the direction of motion. Man #3, in the tunnel, obviously does nothing as he has no snow. Assume negligible friction, and assume no air drag or drag from midair snow -- all that matters here is the mass of any snow on the cart. Who makes it down to the bottom of the slope first, second, and third, and why? ____________________________________________________ Shash, Soulstone, and Laggy are out in the woods chopping trees for wood for a campfire. Shash brings back 6 logs, while Soulstone brings back 4 logs. However, later that night, Laggy admits he didn't collect any wood. However, he has 10 coins he is willing to distribute between both Shash and Soulstone if they let him share in the campfire. How does he distribute the coins between the two in a fair and equitable way? (you have to explain your logic) HINT: The answer is not 6 and 4 to Shash and Soulstone. ___________________________________ Emerald, Fractal_Monkey, and Tass need to get to a location 30 miles away. Emerald and Fractal both walk at speeds of 3 mph each, but on a bike, they both go 5 mph. Tass can walk at 5 mph, but on a bike, he can go 15 mph. However, they only have one bike, and only one person can use the bike at any time. What is the shortest amount of time required to get all three of them to the location 30 miles away? What is your strategy? _____________________________________ Here's one to get you started. Imagine that the hour and minute hands of a clock are the same length. Imagine, also, that I am able to read the hands with 100% certainty (meaning I can tell EXACTLY how far the hour/minute hands have moved). How many times exist over a 12 hour period where, if I were to look at the clock, I'd be unable to tell you what time it was? Last edited by MrRubix_MK5; 08-5-2008 at 02:36 PM.. |
|
|
|
|
|
#2 |
|
FFR Player
|
Is this for the 24hrs, or 12hrs?
__________________
I have a sig. |
|
|
|
|
|
#3 |
|
Housekeeper
Join Date: Jan 2007
Posts: 2,122
|
Stop ban evading rubix.
|
|
|
|
|
|
#4 |
|
FFR Player
Join Date: Apr 2005
Location: Manchester, England
Posts: 464
|
11 over the course of 12 hours. 22 in one day if you can differentiate between AM and PM. The minute hand will do 12 circuits in the time it takes for the hour hand to do one, so the hands overlap every 12/11 of an hour, or every 65.4545... minutes.
|
|
|
|
|
|
#5 | |
|
FFR Player
|
Quote:
Edit: Also, does it matter where the second is?
__________________
I have a sig. Last edited by MahouMinachan; 08-4-2008 at 10:21 AM.. |
|
|
|
|
|
|
#6 |
|
⁽ ´ཀ`⁾
|
you can also tell if its 1:00, 2:00, 3:00 etc.
__________________
|
|
|
|
|
|
#7 |
|
Banned
Join Date: Jul 2008
Posts: 120
|
There is no second hand. Only a minute and hour hand. However, you can read the hands with perfect certainty (e.g. "The hour hand has moved X degrees and the minute hand has moved Y degrees").
Furthermore, mind you, the clock hands move as an actual clock hands would move. So, you can't say that 3:00 is indistinguishable from 12:15 because the hour hand would have moved slightly at the latter time. BTW: 22 times in 24 hours = incorrect Last edited by MrRubix_MK5; 08-4-2008 at 10:36 AM.. |
|
|
|
|
|
#8 |
|
FFR Player
Join Date: Feb 2008
Posts: 76
|
Is the answer 24?
|
|
|
|
|
|
#9 |
|
Banned
Join Date: Jul 2008
Posts: 120
|
No
|
|
|
|
|
|
#10 |
|
FFR Veteran
Join Date: Dec 2007
Location: Texas
Posts: 1,569
|
How about 72 and a half?
Also rubix, I love how they stopped banning your multiple accounts. |
|
|
|
|
|
#11 |
|
Banned
Join Date: Jul 2008
Posts: 120
|
To make this more clear, I've changed the question to ask about a 12-hour period (so you don't need to distinguish between am and pm)
|
|
|
|
|
|
#12 |
|
Absurd
|
6? =/
|
|
|
|
|
|
#13 |
|
Custom User Title
|
You can never tell us the time if you can't distinguish between the two hands.
__________________
|
|
|
|
|
|
#14 |
|
FFR Veteran
Join Date: Dec 2007
Location: Texas
Posts: 1,569
|
Itmorr is correct. If the hands are identical, then you can't distinguish what time it is. Of course, if you are constantly watching the clock, you will be able to tell the difference, but seeing as you said when you can't read it, you obviously aren't watching it constantly.
|
|
|
|
|
|
#15 |
|
FFR Player
Join Date: Feb 2005
Location: England
Posts: 1,031
|
4 times?
__________________
Frank Lee Morris Μήπως πραγματικά πνιγεί;
|
|
|
|
|
|
#16 |
|
FFR Veteran
Join Date: May 2008
Location: England, UK
Age: 34
Posts: 678
|
12, because the minute hand would be directly over the hour hand once every hour, right?
|
|
|
|
|
|
#17 |
|
Banned
Join Date: Jul 2008
Posts: 120
|
Guys if you're going to just guess random numbers, I'm not going to say whether or not they are correct, lol. You have to explain your thought process.
|
|
|
|
|
|
#18 |
|
FFR Player
|
Okay, I made a chart, and none of the hand-minute angles corresponded, so I'll say you can always tell exactly what time it is.
__________________
I have a sig. |
|
|
|
|
|
#19 |
|
Banned
Join Date: Jul 2008
Posts: 120
|
Incorrect
If I said the hands looked like this: | | |_____ What time would you tell me that is? |
|
|
|
|
|
#20 | |
|
FFR Player
Join Date: Feb 2005
Location: England
Posts: 1,031
|
Quote:
12:15 or 3.00 ?
__________________
Frank Lee Morris Μήπως πραγματικά πνιγεί;
|
|
|
|
|
![]() |
| Currently Active Users Viewing This Thread: 1 (0 members and 1 guests) | |
|
|