Math Problems for Credits (The Game)

[madmatt621]

Since Leo made two threads dedicated to solving a math problem, I decided to make a game dedicated to doing the same thing.

Math problem for credits!!
Math problem for credits 2!!

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Each correct answer will be worth 250 credits, 500 credits, 1000 credits, or more; depending on the difficulty.


DO NOT PLAY IF YOU DO NOT HAVE THE CREDITS!!!


When it's you turn, you have to make a math problem, post it, and tell people whether it's right or not. Your math problem must be solvable to the answer you have. If nobody is able to solve the problem, you may post another.


You must have the credits ready when the question is answered correctly.

[madmatt621]

If x2 + y2 = 100, and xy = 18, find the value of x - y.

Worth: 250 credits

[gabgabo]

Originally Posted by madmatt621

If x2 + y2 = 100, and xy = 18, find the value of x - y.

Worth: 250 credits

Something is wrong with this, as we don't know which one will be X or Y, how can we just simply say "That'll be X and that'll be Y". Look, I'll do the same thing but way easier:

If A+B=5 and A*B=6, what would A-B worth?

One of the letter is 3 and the other is 2. The answer may be either 1 or -1.

[emerald000]

Let me give a try at this.

y=18/x and x^2+y^2=100

x^2+(18/x)^2=100
x^2+324/x^2=100
(x^4+324)/x^2=100
x^4+324=100x^2
x^4-100x^2+324=0

x^2=(100±sqrt(10000-4*324))/2
x^2=(100±sqrt(8704))/2
x^2=(100±16sqrt(34))/2
x^2=50±8sqrt(34)
x=±sqrt(50±8sqrt(34))
x=±4±sqrt(34)

x1=-4-sqrt(34)
x2=-4+sqrt(34)
x3=4-sqrt(34)
x4=4+sqrt(34)

y1=4-sqrt(34)
y2=4+sqrt(34)
y3=-4-sqrt(34)
y4=-4+sqrt(34)

x1-y1=-8
x2-y2=-8
x3-y3=8
x4-y4=8

Answer: {±8}

[madmatt621]

emerald got it.

I must ask you if you have the credits to enter an equation.

[emerald000]

I have way too much credits on my hands. After some thinking of a math problem, here's what I came up with:

Solve this system of equation:

x^4+y^4+z^4+1^4 = (y+x+z+1)^4
y^3+z^3+x^3+1^3 = (z+y+x+1)^3
z^2+x^2+y^2+1^2 = (x+z+y+1)^2

1000 credits to the winner.

[kibbel]

oh yea, I give 500 credits if you can answer my question

[kibbel]

I can get the answer to that, it's not tough, just rediculously long... up to 256 characters I believe...

well I might write it out if someone can answer this -

do there exist two irrational numbers p , q such that p^q is rational?

[bluguerrilla]

Originally Posted by kibbel

I can get the answer to that, it's not tough, just rediculously long... up to 256 characters I believe...

well I might write it out if someone can answer this -

do there exist two irrational numbers p , q such that p^q is rational?

I dunno, e^Ln(2).

Edit: Oh, I have to post a problem now... brb...

When does 6*8 = 42?

Reward: 48 credits.

Edit2: = emerald, {x,y,z} = {0,0,0}

[Gibson63]

omg i hate maths..its like chinese to me.... sdaksjdkasd

[Roy Campbell]

Answer: In base 13.

Problem: If 3^(x^2) = 10^(1134^1337), what does x equal? Must be written in scientific notation and coefficient must be rounded to zero decimal places.

Your reward: 1,000 credits.

[madmatt621]

Originally Posted by Roy Campbell

Problem: If 3^(x^2) = 10^(1134^1337), what does x equal? Must be written in scientific notation and coefficient must be rounded to zero decimal places.

Your reward: 1,000 credits.

x=1.46

[emerald000]

You got it bluguerrilla. There is no 256 characters. :P Sending the credits.

Answer to Roy: {±3*10^828} Gimme my 1000 credits back.

[Roy Campbell]

Madmatt: You left some stuff out.

Emerald: You're on the right track, but you're off.

[bluguerrilla]

+/-1e2042?

What's the area under the curve 1/x from 1 to a where a > 1?

Reward: 1060 credits.

[madmatt621]

Originally Posted by bluguerrilla

What's the area under the curve 1/x from 1 to a where a > 1?

a) 1; b) 3/2; or c) -2/3

[Roy Campbell]

Correct. 1,000 credits is coming your way....

Edit: sent

[GuidoHunter]

Uh, zero? You're asking for an infinitesimally small number that has no actual value, only a limit which tends to zero.

--Guido

http://andy.mikee385.com

[bluguerrilla]

Sorry, I should have been more clear:

What's the area under the curve f(x) = 1/x from x = 1 to x = a and a > 1.



For a follow up question that's worth 2234 credits:

What's the area under the curve f(x) = 1/x from x = -a to x = a for any a in element of the reals and why?

(follow up question is hard)

[GuidoHunter]

Are you looking for ln(a)-ln(1) = ln(a)? Because without a defined value for a, no numerical value is possible.

Follow-up: zero? It's an odd function.

--Guido

http://andy.mikee385.com