halp!
Thanks
I already know the answer, I just don't quite get the process.
Thanks
I already know the answer, I just don't quite get the process.
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Re: [College - Calculus 1] Definite Integrals & Substitution
bump. Calling all Rubix!
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Re: [College - Calculus 1] Definite Integrals & Substitution
Gah, I start learning this stuff in a month. You couldn't have waited? :P
I'm still trying to manipulate everything though based on what I know but I haven't come up with anything yet.Comment
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Re: [College - Calculus 1] Definite Integrals & Substitution
I think the d/dx and the integral cancel, leaving e^(x^2)
then I plugged in the upper bound minus the lower bound and got:
(e^cos^2(x))-e
not sure if this is right tho.
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Re: [College - Calculus 1] Definite Integrals & Substitution
Fundamental Theorem of Calculus states that the answer is e^(cos^2(x)) (-sin(x))
Here's the wiki if you need to reference to it:
EDIT: Oh oops, you need to use Chain Rule too. Forgot cos(x) is a function of x lol.Last edited by iironiic; 12-1-2010, 09:10 PM.Comment
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Re: [College - Calculus 1] Definite Integrals & Substitution
iirc substitute cos(x) in place of t, change dt into dx, and append the derivative of cos(x) onto the back
derivative and the integral "cancel out", as you might say, and you're left with [e^(cosx)^2]*(-sinx)We climb up a lot of ladders, and fall down a lot of chutes.Originally posted by Gundam-Dude
Taking "all" oddjobs! PM me requests. Requests filled: 2 last active Mar. 6th, 2017
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Re: [College - Calculus 1] Definite Integrals & Substitution
iirc substitute cos(x) in place of t, change dt into dx, and append the derivative of cos(x) onto the back
derivative and the integral "cancel out", as you might say, and you're left with [e^(cosx)^2]*(-sinx)We climb up a lot of ladders, and fall down a lot of chutes.Originally posted by Gundam-Dude
Taking "all" oddjobs! PM me requests. Requests filled: 2 last active Mar. 6th, 2017
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Re: [College - Calculus 1] Definite Integrals & Substitution
Ooooh, so this is why you asked me if I was busy on aim.
You should've just said you needed help with a quick Calc problem. XDComment
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Re: [College - Calculus 1] Definite Integrals & Substitution
Wineandbread, you differentiated e^cos^2x improperly--it should be -2sinxcosx*e^cos^2x (aka -sin2x*e^cos^2x)
I think... XDLast edited by smartdude1212; 12-1-2010, 09:14 PM.Comment
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Re: [College - Calculus 1] Definite Integrals & Substitution
Wineandbread is right.
The answer is (-e^cosx^2)*(sinx)
EDIT: This teacher is evil... I just solved an area problem using the Mean Value Thm. for Integrals and the answer was 1.553. And yes, it's the correct answer, I checked.
Who the hell writes a problem with that weird of an answer? I was surprised I got it right.Last edited by rushyrulz; 12-1-2010, 09:17 PM.
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Re: [College - Calculus 1] Definite Integrals & Substitution
Okay **** me I better run off and shoot myself before I spread the disease.Comment
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Re: [College - Calculus 1] Definite Integrals & Substitution
Okay someone tell me what I'm doing wrong on this one:
I'm guessing I need to evaluate the antiderivative at F(b)-F(a)
When I integrate 4sec^2(x)-pi/x^2 I get: 4tanx-pi/x.
Is it just me or is tan(-pi/2) divide by 0?
I'm not getting a solution here.. if there even is one.
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Re: [College - Calculus 1] Definite Integrals & Substitution
you take the derivative with respect to the boundary, not the (cosx)^2
Hope your calc class takes a turn for the better rushy My 3D calc class is killing me all over the place right now
We climb up a lot of ladders, and fall down a lot of chutes.Originally posted by Gundam-Dude
Taking "all" oddjobs! PM me requests. Requests filled: 2 last active Mar. 6th, 2017
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Re: [College - Calculus 1] Definite Integrals & Substitution
Wineandbread, are you taking multivariable? I'm probably going to take that next year...Comment
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