Math problems

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  • #16
    FFR Veteran
    ruferddude
    • Oct 2004
    • 165

    Re: Math problems

    Well I live in Texas so my Math classes are weird O.o
    I'm considered "advanced" so in seventh grade I took Pre-Algebra. Eigth grade was Algebra I. Ninth grade was Geometry. Tenth grade was Algebra II. Now I'm about to be in Pre-Calculus. Then AP Calculus as a senior. If you aren't "advanced" then you take everything a year later than me (you finish off with Pre-Calculus as a senior). I don't know where "functions and relations" rank in my education system.
    Originally posted by darkshark
    Speedmods are for losers.
    Originally posted by Tasselfoot
    all the cool kids use 1x.

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    • #17
      FFR Player
      og4lif
      • Jul 2007
      • 38

      Re: Math problems

      lol actually im takin calculus and vectors right now i finished that course a year ago



      functions and relations is pre-calculus

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      • #18
        FFR Player
        NarutoFoxDemon
        • Oct 2006
        • 1181

        Re: Math problems

        Originally posted by ruferddude
        Ah. You guys are right. I didn't see that I was dividing by 0. I feel dumb now.

        I should have seen it. ><
        Thanks for pointing this out and thanks for showing me how dumb I am. ><
        And sorry for the misplacement. I didn't realize the answers were so easy to get. I thought it would take some actual thought to figure out but I come back 10 minutes later and like 8 people figured them both out.

        Edit: Now I feel doubly dumb. ; ; On the video that I posted to make things more clear, like two people pointed out that it was dividing by zero on their comments. The whole second equation could have been left out if I only had read YouTube comments.

        Shame shame, dividing by zero.

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        • #19
          FFR Player
          solopro
          • May 2006
          • 448

          Re: Math problems

          The second statement, I've looked at it and it's interesting. There's also something on Wikipedia I've seen that says zero is equal to one.
          Originally posted by John O'Hurley
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          • #20
            FFR Player
            lord_carbo
            • Dec 2004
            • 6222

            Re: Math problems

            0.99999999999 repeating = 1.

            I win. Infinitesimals win. That ****ing dumbass 11th grade math 10th grader at my lunch table who insists I'm wrong about all of this loses.
            Last edited by Squeek; 08-26-2007, 03:53 AM. Reason: 99 != 1
            last.fm

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            • #21
              FFR Player
              silvercomet1525
              • Sep 2005
              • 601

              Re: Math problems

              Originally posted by lord_carbo
              0.99999999999 repeating = 1.
              Yup. This website may help for anyone who thinks otherwise. Nine different proofs on there.
              Originally posted by Phynx
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              • #22
                FFR Player
                og4lif
                • Jul 2007
                • 38

                Re: Math problems

                Originally posted by og4lif
                X = variable

                (1/sin^2 X) + (1/cos^2 X) = (tan X + 1/tan X)^2
                no calculators 4 this 1
                We already figured that out but can any1 solve this?

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                • #23
                  FFR Player
                  vifs
                  • Apr 2007
                  • 52

                  Re: Math problems

                  Originally posted by og4lif
                  We already figured that out but can any1 solve this?
                  umm... X = 2 dozen boxes of Pi

                  lol i could most likely solve it if i was in school, im pretty much shut down even though school started in 4 days


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                  • #24
                    FFR Player
                    MrRubix
                    • Nov 2026
                    • 8340

                    Re: Math problems

                    I'm a little rusty when it comes to trig identities but here goes:

                    (1/sin^2X) + (1/cos^2X) = (tan X + 1/tanX)^2

                    First I'd combine the first two terms:

                    (cos^2X+sin^2X)/(sin^2X*cos^2X) = (tan X + 1/tanX)^2

                    The numerator, cosX^2 + sin^2X, is equal to 1:

                    1/(sin^2X*cos^2X) = (tan X + 1/tanX)^2

                    This is the same as:

                    (1/(sinX*cosX))^2 = (tan X + 1/tanX)^2

                    So now we are basically trying to equate the things within the second-power-raise, so we aim to equate 1/(sinX*cosX) and tan X + 1/tanX.

                    Since tan = sin/cos and 1/tan or cot = cos/sin, we see that the right hand side is basically sin/cos + cos/sin, so we have two instances of each. Currently, the left hand side has half as many instances. Therefore we should try to prove this by simplifying the right-hand side:

                    tanX + 1/tanX
                    We then change tanX into tan^2X/tanX so we can combine like terms:
                    (1 + tan^2X)/tanX
                    And change our tangents into their sine and cosine equivalents:
                    (1 + (sinX/cosX)^2)/(sinX/cosX)
                    We then change the 1 into cos^2X/cos^2X so we can combine it as a like term later:
                    ((cos^2X/cos^2X) + (sin^2X/cos^2X))/(sinX/cosX)
                    Combining terms:
                    (((cos^2X + sin^2X)/cos^2X))/(sinX/cosX)
                    cos^2X + sin^2X is equal to 1:
                    (1/cos^2X)/(sinX/cosX)
                    Then we simplify things a bit:
                    cosX/(sinX*cos^2X)
                    And finally drop the common cosX from the numerator and denominator:
                    1/(sinX*cosX)

                    Since we just proved 1/(sinX*cosX) = tanX + 1/tanX, we therefore prove:

                    (1/(sinX*cosX))^2 = (tan X + 1/tanX)^2

                    And since we showed that (1/sin^2X) + (1/cos^2X) = (1/(sinX*cosX))^2, we therefore prove:

                    (1/sin^2X) + (1/cos^2X) = (tan X + 1/tanX)^2

                    Edit: Oh yeah, QED
                    Last edited by MrRubix; 08-26-2007, 11:43 AM.
                    https://www.youtube.com/watch?v=0es0Mip1jWY

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                    • #25
                      FFR Player
                      og4lif
                      • Jul 2007
                      • 38

                      Re: Math problems

                      good job rubix you don't look that rusty too me
                      must have taken a while too get that all down

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                      • #26
                        FFR Player
                        Relambrien
                        • Dec 2006
                        • 1644

                        Re: Math problems

                        For anyone too lazy to understand the (1/3) + (1/3) + (1/3) = 1 thing, I'll write an explanation that hopefully most can understand.

                        First, 1/3 = 0.333...

                        The "..." means that the sequence repeats infinitely, to the point where the last digit is a "3" and you cannot add a zero after that. It may sound weird, but trust me, that's the simplest explanation.

                        Now with simple algebra, we can understand more things.

                        0.333... = 1/3
                        0.999... = 1 (Multiply each side by 3)

                        But how can this be true? This is how:

                        Oh, and the space filter makes this a little hard to read. Sorry.

                        Let c = 0.999...

                        c = 0.999...
                        10c = 9.999... (Multiply each side by 10)
                        9c = 9.000... (Subtract 1c from each side)
                        c = 1.000... (Divide each side by 9)
                        c = 1 (Simplify)
                        0.999... = 1 (Substitution property of equality)

                        Yes, I stole this from Wikipedia.

                        And about the second problem, it just goes to show you that simplifying after every step is key . If you do that, you find out that you get 0=0 early on.
                        Last edited by Relambrien; 08-26-2007, 01:09 PM.

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