Oops I broke the laws of math. - Page 2

**foilman8805** · 10-18-2009, 05:20 PM

ok, i see the problem with proof 2

number 3 might have something to do with taking square roots of negative numbers and getting imaginary numbers??

alexdestructions · 10-18-2009, 05:21 PM

it's still a bit easy, the square roots threw me off though lol

**bLasTamos** · 10-18-2009, 05:22 PM

lol star i don't know why you say proof 3 is the hardest, it has the most screwups

stargroup · 10-18-2009, 05:24 PM

Quote:

Originally Posted by Artic_counter

(1.5) =/= (-0.5)
you can't scratch those little ^2 that way

I think you mean

0.5 =/= -0.5

rofl

but yeah you got the idea

**Darkslave** · 10-18-2009, 05:25 PM

I think I'll pass....I once did something like this on a math test by accident and ended up breaking my head over it for like 10 mins before redoing it completely

**DossarLX ODI** · 10-18-2009, 05:27 PM

Quote:

Originally Posted by stargroup

Alternate version of Proof 3:

1 = √1 = √(-1)(-1) = √-1 * √-1 = -1

Negative times a negative is a positive. √(-1)(-1) would be √1. √-1 * √-1 would be -1, not positive one.

**bLasTamos** · 10-18-2009, 05:31 PM

Quote:

Originally Posted by DossarLX ODI

Negative times a negative is a positive. √(-1)(-1) would be √1. √-1 * √-1 would be -1, not positive one.

?

Quote:

Originally Posted by stargroup

1 = √1 = √(-1)(-1) = √-1 * √-1

this is right.

Quote:

Originally Posted by stargroup

√-1 * √-1 = -1

this isn't.

stargroup · 10-18-2009, 05:33 PM

√a * √a = a

√-1 * √-1 = -1

???

**bLasTamos** · 10-18-2009, 05:34 PM

Yeah if a is positive.

Prime8 · 10-18-2009, 05:35 PM

Quote:

Originally Posted by DossarLX ODI

Negative times a negative is a positive. √(-1)(-1) would be √1.

That's why stargroup has:

Quote:

Originally Posted by stargroup

√1 = √(-1)(-1)

Quote:

Originally Posted by DossarLX ODI

√-1 * √-1 would be -1, not positive one.

That's the end result

Quote:

Originally Posted by stargroup

√-1 * √-1 = -1

**DossarLX ODI** · 10-18-2009, 05:35 PM

The order of operation says to do the parentheses first, so √(-1)(-1) would have to be √(1). Correct me if I'm wrong.

Edit: Oh thanks Prime

stargroup · 10-18-2009, 05:37 PM

Quote:

Originally Posted by bLasTamos

Yeah if a is positive.

√-x * √y = √-xy

√-1 * √1 = √-1 * 1 = √-1

???

**bLasTamos** · 10-18-2009, 05:39 PM

Quote:

Originally Posted by DossarLX ODI

The order of operation says to do the parentheses first

The expressions in parenthses are already solved, they're both -1.

**bLasTamos** · 10-18-2009, 05:39 PM

Quote:

Originally Posted by stargroup

√-x * √y = √-xy

√-1 * √1 = √-1 * 1 = √-1

???

yeah what's the problem with that?

stargroup · 10-18-2009, 05:47 PM

Quote:

Originally Posted by bLasTamos

yeah what's the problem with that?

Quote:

Originally Posted by bLasTamos

Yeah if a is positive.

I just proved that a can be negative

**bLasTamos** · 10-18-2009, 05:48 PM

Quote:

Originally Posted by stargroup

Proof 5: 1=0

x = 1

(d/dx) x = (d/dx) 1

1 = 0

LOL this one is amazing. Where did you get this from?

**bLasTamos** · 10-18-2009, 05:49 PM

Quote:

Originally Posted by stargroup

I just proved that a can be negative

You're not going anywhere, that doesn't make any sense.

stargroup · 10-18-2009, 05:51 PM

Quote:

Originally Posted by stargroup

√-x * √y = √-xy

√-1 * √1 = √-1 * 1 = √-1

???

√-1 * √4 = √-1 * 2 = √-4 = 2i

Just how does this not make sense?

stargroup · 10-18-2009, 05:55 PM

alright 7 proofs of increasing difficulty

this should be enough to keep you bastards workin for a while

**bLasTamos** · 10-18-2009, 05:58 PM

Quote:

Originally Posted by stargroup

√a * √a = a

√-1 * √-1 = -1

???

You didn't proove that a can be negative.

10-18-2009, 05:20 PM	#21
foilman8805 smoke wheat hail satin Join Date: Sep 2006 Location: LA baby Age: 36 Posts: 5,704	Re: Oops I broke the laws of math. ok, i see the problem with proof 2 number 3 might have something to do with taking square roots of negative numbers and getting imaginary numbers??

10-18-2009, 05:22 PM	#23
bLasTamos FFR Veteran Join Date: Jun 2008 Posts: 137	Re: Oops I broke the laws of math. lol star i don't know why you say proof 3 is the hardest, it has the most screwups

10-18-2009, 05:25 PM	#25
Darkslave :D Join Date: Jan 2008 Location: The Netherlands Age: 32 Posts: 140	Re: Oops I broke the laws of math. I think I'll pass....I once did something like this on a math test by accident and ended up breaking my head over it for like 10 mins before redoing it completely

10-18-2009, 05:33 PM	#28
stargroup FFR Player Join Date: Jun 2007 Posts: 974	Re: Oops I broke the laws of math. √a * √a = a √-1 * √-1 = -1 ??? __________________ (´･ω･`)

10-18-2009, 05:34 PM	#29
bLasTamos FFR Veteran Join Date: Jun 2008 Posts: 137	Re: Oops I broke the laws of math. Yeah if a is positive.

10-18-2009, 05:35 PM	#31
DossarLX ODI Batch Manager Game Manager, Song Release Coordinator Join Date: Mar 2008 Location: USA Age: 29 Posts: 14,869	Re: Oops I broke the laws of math. The order of operation says to do the parentheses first, so √(-1)(-1) would have to be √(1). Correct me if I'm wrong. Edit: Oh thanks Prime

10-18-2009, 05:55 PM	#39
stargroup FFR Player Join Date: Jun 2007 Posts: 974	Re: Oops I broke the laws of math. alright 7 proofs of increasing difficulty this should be enough to keep you bastards workin for a while __________________ (´･ω･`)

Currently Active Users Viewing This Thread: 1 (0 members and 1 guests)