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Easy arithmetic problem
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aperson
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#1
Easy arithmetic problem
05-16-2006, 09:57 PM
For the function
, prove that the real part of the non-trivial zeros is 1/2 for any s
T0rajir0u
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#2
05-16-2006, 10:16 PM
Re: Easy arithmetic problem
lol ap ur cool
http://www.aronpalmer.com/rproofv2.pdf
(Proposed proof someone posted on AoPS awhile back.)
hehe
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DarkManticoreX2
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#3
05-16-2006, 10:19 PM
Re: Easy arithmetic problem
I quit differential equations
Sh!t was hard as hell
You Wrote a paper on Differential equations
I exploded with jealosy
sumation from 1 - infinity of 1 divided by n to the power of s
there i stated it thats basically all i can do from there XD
AAA's = 800
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V
Manti, I apologize for insulting you. Let the record show that I am a prickass douche, and not only that, but that I am a terrible player.
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T0rajir0u
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#4
05-16-2006, 10:32 PM
Re: Easy arithmetic problem
... You don't get it, do you?
Millennium Prize Problems Lecture Series - Clay Mathematics Institute
http://www.claymath.org/millennium/
Page not found - Clay Mathematics Institute
http://www.claymath.org/millennium/Riemann_Hypothesis/
Riemann hypothesis - Wikipedia
http://en.wikipedia.org/wiki/Riemann_Hypothesis
Edit: Actually, ap didn't specify that s was a complex variable, so the way he stated it, there are no zeros. Lol.
hehe
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aperson
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#5
05-16-2006, 10:42 PM
Re: Easy arithmetic problem
Originally posted by
DarkManticoreX2
Words
If I were to awaken after having slept for a thousand years, my first question would be: Has the Riemann hypothesis been proven?
-David Hilbert
But then again it's Hilbert so who cares.
Edit:
Edit: Actually, ap didn't specify that s was a complex variable, so the way he stated it, there are no zeros. Lol.
well then that's a pretty trivial proof isn't it.
Last edited by
aperson
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05-16-2006, 10:48 PM
.
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Tasselfoot
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#6
05-16-2006, 11:02 PM
Re: Easy arithmetic problem
and..........
locked. don't test me ap. you know i'd greatly enjoy banning your ass again.
RIP
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