I work as an online calculus tutor, and one of the problems that I was helping a student with today seemed a little too difficult to do by brute force. I was wondering if there was a more efficient method, or any other way to solve the problem by hand.
The problem asks to find the taylor series representation of:
Ln(x+1)/(1-x)
About x=0
Usually, for functions that have nasty derivatives, there are shortcuts in finding their taylor series which the problem is highlighting for practice. For example, to find it for x^2/(1-x^3), you would take the series for 1/(1-x), the geometric series, replace the x's with x^3 and multiply it by x^2.
Does anyone know how to find an analytic solution using the taylor series of ln(x+1) and/or 1/(1-x)?
The problem asks to find the taylor series representation of:
Ln(x+1)/(1-x)
About x=0
Usually, for functions that have nasty derivatives, there are shortcuts in finding their taylor series which the problem is highlighting for practice. For example, to find it for x^2/(1-x^3), you would take the series for 1/(1-x), the geometric series, replace the x's with x^3 and multiply it by x^2.
Does anyone know how to find an analytic solution using the taylor series of ln(x+1) and/or 1/(1-x)?






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