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Given that the largest pair of prime numbers known is 242206083x2^38880 +- 1. do you think that it will be possible to prove the twin primes conjecture with the relatively newfound idea that the nontrivial roots the Riemann Zeta Function t (s) = (sum)(1/n^s) = (product) (1 - p^-s)^-1 have a real part 1/2 on the complex plane?
Anonymous
01-3-2004, 09:37 PM
no
Anticrombie0909
01-3-2004, 10:20 PM
Ok did what you just said have a point or did you just list a bunch of random equations?
Ok did what you just said have a point or did you just list a bunch of random equations?
do you think that it will be possible to prove the twin primes conjecture
It's all very coherant if you think about what I said.
makaveli121212
01-3-2004, 10:37 PM
easy
well? I for one think that it is possible that the twin prime conjecture be proved soon, what with the proof of the infinite prime conjecture and the fact that prime number fomulae have been greatly developed only recently.
Yanah_God
01-4-2004, 04:29 PM
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my brain is bleeding
i second the bleeding brain
Brainmaster07
01-4-2004, 05:53 PM
It's kind of obvious there are infinite primes dude -_-.
And infinite primes means infinite twin primes.
banditcom
01-4-2004, 06:08 PM
I agree with Brain, given the nature of infinity.
And some parts of your question don't make much sense... it feels like you threw in the math part but didn't make it a complete sentence.
Hmm, perhaps you misunderstand. It's one thing to say there are an infinity of primes or twin primes, but I was pondering whether it will be proven.
Quoth me, w/o math:
'Given that the largest pair of prime numbers known is really big. do you think that it will be possible to prove the twin primes conjecture with the relatively newfound idea that those crazy mathemagicians came up with?"
RobbyZero
01-4-2004, 06:49 PM
I got lost at prime...
Anticrombie0909
01-4-2004, 07:02 PM
Ok...somebody obvoiusly hacked Vx's account or something...
Anticrombie0909
01-4-2004, 07:03 PM
Ok...somebody obvoiusly hacked Vx's account or something...
Ok...someone double posted. ahahahahahahahahahahhahahahaahahahahahhaah I'm awsome.
banditcom
01-4-2004, 08:45 PM
Or maybe he just copied what someone said on another site. :P
Feuergeist
01-4-2004, 08:50 PM
the answer is 12
Anonymous
01-4-2004, 08:52 PM
ya that's what i was thinking he did too
Or maybe he just copied what someone said on another site. :P
I honestly did not.
makaveli121212
01-5-2004, 05:41 AM
yeah you did
heyhey11
01-5-2004, 09:08 AM
I honestly did not.
NO WAY JOSE
squarebear
01-5-2004, 09:36 AM
Given that the largest pair of prime numbers known is 242206083x2^38880 +- 1. do you think that it will be possible to prove the twin primes conjecture with the relatively newfound idea that the nontrivial roots the Riemann Zeta Function t (s) = (sum)(1/n^s) = (product) (1 - p^-s)^-1 have a real part 1/2 on the complex plane?lol, you need to get out more.
altairian
01-5-2004, 09:44 AM
Given that the largest pair of prime numbers known is 242206083x2^38880 +- 1. do you think that it will be possible to prove the twin primes conjecture with the relatively newfound idea that the nontrivial roots the Riemann Zeta Function t (s) = (sum)(1/n^s) = (product) (1 - p^-s)^-1 have a real part 1/2 on the complex plane?lol, you need to get out more.
so very, very owned ;)
the answer is 12
after heavy consideration, and relatively complicated math work.. I second your conclusion
makaveli121212
01-5-2004, 01:51 PM
it hasnt evem been proven by the best mathmagicians in the world, so i wouldnt even try
Anticrombie0909
01-5-2004, 05:45 PM
Ok this thread is retarded...-er
makaveli121212
01-5-2004, 05:52 PM
you know, why do you always go out of your way to say 'this is retarded' or 'you are dumb' or 'shut up n00b' or 'youre a postwhore' or 'youre a quotewhore'...like anyone really cares what you think is retarded or not...you dont like it, fine, but do you need to say it on every single thread you think is dumb...i mean its like youre trying to disguise your postwhoring by trying to act like your the thread police...just stop your whoring all the time
hmm... yea.. this thread is done..
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