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Old 11-8-2007, 01:23 PM   #1
MrRubix
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Default Math Credit Challenge

Ask me any math question (that can actually be solved), and if I get it right, you owe me 100 credits. If I get it wrong, I'll give you 200 credits.
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Old 11-8-2007, 01:28 PM   #2
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Default Re: Math Credit Challenge

www.google.com


but, um, seriously... for 100 credits? solve p = np.
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Old 11-8-2007, 01:29 PM   #3
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Default Re: Math Credit Challenge

lol, brb.

What's the sum of the function f(n,a) = 1/(n^2+a^2) over all n in element of the natural numbers and for any a in element of the complex numbers.

No using math programs.

This is part of my favorite math problem.

Or you could do my favorite problem.

Starting with the geometric series prove that the above sum from 1 -> infinity for a = 0 is equal to pi^2/6 (this doesn't require complex analysis, just creative thinking).
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Last edited by bluguerrilla; 11-8-2007 at 01:43 PM.. Reason: lol....OR
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Old 11-8-2007, 02:00 PM   #4
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Default Re: Math Credit Challenge

5+3=?
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Old 11-8-2007, 02:25 PM   #5
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Default Re: Math Credit Challenge

Find the area of the surface that is part of the sphere x^2 + y^2 + z^2 = 4z that lies inside the paraboloid z = x^2 + y^2.
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Old 11-8-2007, 02:33 PM   #6
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Default Re: Math Credit Challenge

what if i get your question right foilman?
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Old 11-8-2007, 02:37 PM   #7
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Default Re: Math Credit Challenge

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Originally Posted by DrugstoreCowboy View Post
what if i get your question right foilman?
i'd give you the credits. you would just have to post before Rubix does.
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Old 11-8-2007, 02:46 PM   #8
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Default Re: Math Credit Challenge

99=33x? (lawl easyness)
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Old 11-8-2007, 03:47 PM   #9
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Default Re: Math Credit Challenge

If you want a challenge check out the one that destiny posted.
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Old 11-8-2007, 03:55 PM   #10
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Default Re: Math Credit Challenge

What is the square root of -1
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Old 11-8-2007, 04:05 PM   #11
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Default Re: Math Credit Challenge

shoot tass beat me to p = np lol
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Old 11-8-2007, 04:38 PM   #12
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Default Re: Math Credit Challenge

Quote:
Originally Posted by MagicCarpetRide View Post
What is the square root of -1
you may as well have said what's 5+3, except the answer to yours can be typed more quickly

two trains leave chicago at different times going in different directions when do they meet up
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Old 11-8-2007, 04:47 PM   #13
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Default Re: Math Credit Challenge

Darn, I used to know how to do that one foilman. I could probably try to dig up my calc 3 notes, but I'm too lazy
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Old 11-8-2007, 05:35 PM   #14
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Default Re: Math Credit Challenge

1 13 77 294 855 2071 ...

A formula exists which will allow you to determine the sum of the first N terms of the infinite series above. What is the formula and what is the sum of the first 10 terms?

I can make harder ones if you desire >__>
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Old 11-8-2007, 05:40 PM   #15
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Default Re: Math Credit Challenge

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Originally Posted by Shouka View Post
Darn, I used to know how to do that one foilman. I could probably try to dig up my calc 3 notes, but I'm too lazy
good luck trying to use Calc III to find that out.
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Old 11-8-2007, 06:18 PM   #16
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Default Re: Math Credit Challenge

Quote:
Originally Posted by dAnceguy117 View Post
you may as well have said what's 5+3, except the answer to yours can be typed more quickly
Actually they could be typed just as fast....
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Old 11-8-2007, 06:22 PM   #17
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Default Re: Math Credit Challenge

If two people are having sex and a third one joins in, how many people are there?

Think carefully...

^_^
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Old 11-8-2007, 06:45 PM   #18
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Default Re: Math Credit Challenge

thread sucks
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Old 11-8-2007, 08:36 PM   #19
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Default Re: Math Credit Challenge

How about the Riemann Hypothesis?

...

Okay, is all seriousness... what is the next number in this sequence:

6, 35, 143, 323, 667, 1147, 1763, 2491, 3953, 5183...

Ten numbers should be enough to get rid of ambiguity of the sequence.
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Last edited by silvercomet1525; 11-8-2007 at 08:38 PM.. Reason: 200 credits isn't much at all, but why not?
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Old 11-8-2007, 09:47 PM   #20
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Default Re: Math Credit Challenge

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Originally Posted by silvercomet1525 View Post
How about the Riemann Hypothesis?

...

Okay, is all seriousness... what is the next number in this sequence:

6, 35, 143, 323, 667, 1147, 1763, 2491, 3953, 5183...

Ten numbers should be enough to get rid of ambiguity of the sequence.
D:

It should proceed, after 2491...3599, 4757, 5767...etc.

You missed a value >_>...!
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Last edited by Reach; 11-8-2007 at 09:54 PM..
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