05-1-2007, 06:28 PM | #1 |
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Patterns (For the math geeks)
The rules are simple. Post several numbers of a pattern you developed. The next member in line writes a formula that will result in the pattern, using x as the place in line of the number. For example, if the pattern was 2,4,6,8... the formula would be 2x. Always start the pattern off where x=1. Do not make them to overly complicated... at least in the beginning anyway. In order to post a pattern you must solve the last persons pattern correctly. Make sure your formula fits for all numbers they posted.
The first sequence: 1, 3, 6, 10, 15, 21, 28, 36, 45, 55... |
05-1-2007, 06:31 PM | #2 |
Falcon Paaaauuuunch!!!!!!
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Re: Patterns (For the math geeks)
Triangular numbers, as in 1+2+3+...+n for the nth term.
Next sequence is 1, 2, 4, 8, 16, 32, 64, 128 (yea, really easy)
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05-1-2007, 06:39 PM | #3 |
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Re: Patterns (For the math geeks)
y=2n
1, 3, 5, 7, 11, 13, 17, 19, 23... I think all those are right. |
05-1-2007, 06:43 PM | #4 |
Falcon Paaaauuuunch!!!!!!
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Re: Patterns (For the math geeks)
Are those supposed to be primes? If so, 2 should be on the list, and not 1.
Edit: and mine was NOT 2n, it was 2^n.
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Last edited by Doug31; 05-1-2007 at 06:53 PM.. |
05-1-2007, 06:45 PM | #5 |
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Re: Patterns (For the math geeks)
+2
.3333, .1111, .0370, .0123, .0041
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05-1-2007, 06:50 PM | #6 |
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Re: Patterns (For the math geeks)
^^^^^^^^^^
a(n) = (1)/(3^n) new: 1, 4, 27, 256, 3125, 46656, 823543 |
05-1-2007, 06:52 PM | #7 |
Falcon Paaaauuuunch!!!!!!
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Re: Patterns (For the math geeks)
x^x
Next one is: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144...
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05-1-2007, 06:53 PM | #8 |
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Re: Patterns (For the math geeks)
Add all previous numbers.
5000, 3125, 685.871, 76.293, 5.12
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Last edited by Fantasticone; 05-1-2007 at 06:55 PM.. |
05-1-2007, 06:53 PM | #9 |
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Re: Patterns (For the math geeks)
It's not add ALL previous numbers, it's just adding the most recent 2.
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05-1-2007, 07:10 PM | #10 |
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Re: Patterns (For the math geeks)
Cough cough.
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05-1-2007, 07:23 PM | #11 | |
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Re: Patterns (For the math geeks)
Quote:
2 x 2 = 4 4 x 2 = 8 8 x 2 = 16 16 x 2 = 32 32 x 2 = 64 64 x 2 = 128 Let n represent the previous number in the sequence. f(n)=2n Doug or someone else please tell me how that is wrong. Dont mean to bitch i just wanna know XD Last edited by brothaice; 05-1-2007 at 07:26 PM.. |
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05-1-2007, 07:27 PM | #12 | |||
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Re: Patterns (For the math geeks)
You are partly correct.
The equation for the NEXT term in this series is 2n, but the series as a whole is defined by 2^n. Also, I have no clue on Fantasticone's one. My guess is that there is none XD
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05-1-2007, 07:28 PM | #13 |
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Re: Patterns (For the math geeks)
500{1/(.n/n)}^n
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05-1-2007, 07:30 PM | #14 |
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Re: Patterns (For the math geeks)
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05-1-2007, 07:37 PM | #15 |
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Re: Patterns (For the math geeks)
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05-1-2007, 07:38 PM | #16 |
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Re: Patterns (For the math geeks)
Thought you were math geeks.
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05-1-2007, 07:44 PM | #17 |
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Re: Patterns (For the math geeks)
It's so hard, I still don't get it. Wouldn't .n/n always equal 1/10? And then 1/(1/10) would always be 10, so it would just be 500*10^n? That doesn't work, but this isn't making sense to me lol.
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05-1-2007, 07:48 PM | #18 |
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Re: Patterns (For the math geeks)
Oh **** I added extra brackets or whatever.
500(1/.n/n)^n There we go.
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05-1-2007, 08:05 PM | #19 |
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Re: Patterns (For the math geeks)
New pattern plz. I would write one, but its more fun figuring out you guys'.
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05-1-2007, 08:13 PM | #20 |
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Re: Patterns (For the math geeks)
.0349, .0697, .1046, .1395
Im so evil.
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Last edited by Fantasticone; 05-4-2007 at 10:11 PM.. |
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