Old 05-16-2006, 11:57 PM   #1
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Default Easy arithmetic problem

For the function , prove that the real part of the non-trivial zeros is 1/2 for any s
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Old 05-17-2006, 12:16 AM   #2
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Default Re: Easy arithmetic problem

lol ap ur cool

http://www.aronpalmer.com/rproofv2.pdf

(Proposed proof someone posted on AoPS awhile back.)
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Old 05-17-2006, 12:19 AM   #3
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Default Re: Easy arithmetic problem

I quit differential equations

Sh!t was hard as hell

You Wrote a paper on Differential equations

I exploded with jealosy

sumation from 1 - infinity of 1 divided by n to the power of s

there i stated it thats basically all i can do from there XD
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Old 05-17-2006, 12:32 AM   #4
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Default Re: Easy arithmetic problem

... You don't get it, do you?

http://www.claymath.org/millennium/
http://www.claymath.org/millennium/Riemann_Hypothesis/
http://en.wikipedia.org/wiki/Riemann_Hypothesis

Edit: Actually, ap didn't specify that s was a complex variable, so the way he stated it, there are no zeros. Lol.
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Old 05-17-2006, 12:42 AM   #5
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Default Re: Easy arithmetic problem

Quote:
Originally Posted by DarkManticoreX2
Words
If I were to awaken after having slept for a thousand years, my first question would be: Has the Riemann hypothesis been proven?
-David Hilbert




But then again it's Hilbert so who cares.


Edit:
Quote:
Edit: Actually, ap didn't specify that s was a complex variable, so the way he stated it, there are no zeros. Lol.
well then that's a pretty trivial proof isn't it.
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Old 05-17-2006, 01:02 AM   #6
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Default Re: Easy arithmetic problem

and..........


locked. don't test me ap. you know i'd greatly enjoy banning your ass again.
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