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#1 |
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Been doing Calc all day... can someone help me out with this integral? It would mean the world!
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Last edited by JKPolk; 02-15-2007 at 06:52 PM.. |
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#2 |
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FFR Player
Join Date: Jun 2006
Location: New York
Age: 29
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Sorry I cannot help,
But how did you write the formula? What program did you use? |
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#3 |
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What do you need to solve for?
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#4 |
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FFR Player
Join Date: May 2006
Location: Texas
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Message removed due to hi19hi19
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Last edited by LifereaperX; 02-16-2007 at 02:14 AM.. |
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#5 |
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Carls, Girls, & Drugs
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*head explodes*
...Seriously though. Ow. That hurt my head just looking at it.
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http://dozemusic.com/ |
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#6 |
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Falcon Paaaauuuunch!!!!!!
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Is there any more information you can give us on this problem? Right now, it looks like a trig substitution or something, but I don't see how to do it, unless you know more about this problem.
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#7 |
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FFR Player
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Message removed due to hi19hi19
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Last edited by LifereaperX; 02-16-2007 at 02:14 AM.. |
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#8 |
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FFR Player
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Message removed due to hi19hi19
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Last edited by LifereaperX; 02-16-2007 at 02:15 AM.. |
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#9 |
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I can't tell if you guys are being idiots on purpose or what.
If had taken another year of math in university I'd be able to help you out. Unfortunately, I probably can't tell you anything you don't already know, as I only just barely touched on integrals.
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C is for Charisma, it's why people think I'm great! I make my friends all laugh and smile and never want to hate! |
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#10 | ||
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FFR Player
Join Date: Aug 2005
Posts: 73
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That looks like a double integral if I had to say anything about it, or, perhaps, an integral with more than one variable. Way above what I can help with.
Can you try separating the integrals by variable and then integrating them?[/pretending to know what I'm talking about]
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#11 |
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Private College
Join Date: Feb 2006
Location: Lol badger
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If you don't have to evaluate it the proper way, you can always recognize that it has perfect radial symmetry and convert it to a single integral.
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<img src="Bent Lines" /> |
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#12 |
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lets see
can you use a triangle with sides a, r, and (a^2+r^2)^.5? |
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#13 |
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Message removed due to hi19hi19
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Last edited by LifereaperX; 02-16-2007 at 02:15 AM.. |
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#14 |
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is against custom titles
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I'd say trig substitution as well, but it's been way too long since I did Cal II or Cal III, so I have no idea which to do.
I also spy a Jacobian, not that that's of any import, here. --Guido http://andy.mikee385.com |
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#15 | |
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LifeReaper, this is the CT forum... please stop?
EDIT: your math is wrong anyways. 4!=-2^(2) exponents take precedence over most other mathematical signs, so -2^(2) equates to -4 not 4.
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Last edited by spyke252; 02-15-2007 at 10:08 PM.. |
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#16 | |
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tool
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You DO spy a Jacobian. Nice eye. I wrote the expression MSWord using Equation Editor, and just SSd it and imageshacked it.
The equation is written correctly, it is solvable. It is a double integral, so one has to evaluate the inner integral first with respect to r, and then evaluate the result with respect to theta. I don't think trig substitutions would really help, as this is already in polar coordinates and using trig would probably only create a small catastrophe. I've tried using u substitution and integration by parts but I just can't seem to crack the code. Quote:
And to those who are asking what to solve for, it should come out to be a number with respect to the variable 'a,' I'm not really trying to solve for anything, seeing as this isn't an equation. Thanks for your input, I'm gonna keep plugging away at this until I pass out probably!
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#17 |
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Message removed due to hi19hi19
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Last edited by LifereaperX; 02-16-2007 at 02:15 AM.. |
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#18 | |
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Quote:
Which = -4. What you are saying is (-2)^2, rather than -2^2.
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#19 |
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tool
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OK so I eventually got it. I split it up into two integrals, distributing the r at the end into each factor and integrating the first and second sections separately. Thanks for the suggestions on how to tackle it!
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#20 |
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If this was differential calc we probably would have been of a bit more help, but then of course you probably wouldn't be asking for help
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