[FissionMailed1]

It will call Animal's make_sound() function, yes. However, if Animal's make_sound() function is pure virtual, it will look at what type of object Animal is pointing to (in this case, a cat) and call that implementation of make_sound() instead. It will just the data attributes it inherited from animal (if there is any) and the data attributes from Cat when executing make_sound().

Oh, I should also mention, pure virtual is declared as follow:

virtual void foo() = 0;

EDIT: Sorry, I misread your post. my post is assuming that you are executing this:

Animal* kitty = new Cat();
kitty->make_sound();

EDIT 2: I need to go eat some food or something, not thinking straight. If you do something like this:

Cat* kitty = new Cat();
kitty->make_sound();

This would also be valid code as well, and will perform exactly the same as the code snippet in my first edit.