09-28-2012, 09:53 AM
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#22
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Woof
Join Date: Jan 2006
Location: MA
Posts: 173
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Re: Continuin to fail at Java
Do you mean something like this?
Code:
for (int x = 0; x < condition; x++)
{
for (int y = 0; y < x; y ++)
{
System.out.println(y);
}
}
// For x = 3, prints out 0, 0, 1, 0, 1, 2
It goes through the for-loop condition-many times, then it'll go through another for-loop condition-many times with the current x-value as its limit every time. I hope that helps in some way.
Last edited by powerfull; 09-28-2012 at 11:22 AM..
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