[Wiosna]

Originally Posted by Dynam0

The range of the perfect window for this sequence is 6 frames. Mr. Cheese, playing as slowly as possible, needs to hit a note on Frame 1, Frame 3 or 4, and then Frame 6. In essence, Mr. Cheese will need to make 3 inputs separated by 2.5 frames each. We've already established that one frame is equivalent to the space between 16th notes in a 450bpm stream. 2.5 frames would be the space between notes in a 450 / 2.5 = 180bpm 16th stream, meaning Mr. Cheese has to execute a 3-note 16th jack at 180bpm that starts and ends frame perfectly in order to cheese this pattern.

Are you sure that this is correct? I'm very sure that you can hit the 2-framer pattern that you screenshotted at 150bpm 16ths.

When jacking at 180bpm, each note is separated by 87.5ms.
The earliest possible input where Mr. Cheese can get a perfect is -50ms. 
The notes are placed at 0ms, 66.6ms and 100ms respectively 
(frame 2, frame 4, frame 5 in your example).
 
Time	Input	Difference
0ms	-50ms	-50ms	
66.6ms	37.5ms	-29.16ms
100ms	125ms	+25ms

Given that there is an additional +25ms of leeway for 2 inputs (2nd and 3rd note of the jack), 
Mr. Cheese can jack 12.5ms slower per note and would still obtain perfects.

87.5ms + 12.5ms per note = 100ms per note = 10 notes per second = 150bpm 16ths.

The issue in your calculation, I believe, is that the gap between the start of frame 1 and the end of frame 6 is 6 frames, not 5. The start of frame 1 and end of frame 6 constitute virtually no frames at all, since they're specific points in time and not periods of time.

With that said...

Homework: Find a section that is more demanding than the above example and describe how Mr. Cheese would attack it. You cannot use Whimper Wall, vRofl, Crowdpleaser v1, P4U v1, etc.

Sinthasomphone has 2 5-note jacks (e.g. combo 805), with each note in the jack being separated by 2 frames (66.67ms) each. Assuming that Mr. Cheese hits the first note of the jack in the earliest part of the perfect window (-50ms), Mr. Cheese has 100ms leeway over 4 notes. Combining the leeway per note and the distance between each note, Mr. Cheese has to jack at about 91.67ms per note, or about 163.63bpm 16ths. This is strictly harder than a 150bpm 16th 3-note jack.

I'm sure there are a few other examples, but the general idea is to find charts with practically consecutive 1-frame minijacks with 2-note gaps (e.g. xx-x-xx) or a 2-frame jumpjack but the jump is separated by 1 frame each (since Mr. Cheese would have an 66.67ms window instead of a 100ms window -- the optimal position to hit these kinds of grace jumpjacks would be 16.67ms before the first note since the second note comes 33.33ms after), but I can't think of many concrete examples.