[LongGone]

For 100, we have 25 odd primes (including 1), and one even 2. The sum of 25 odd primes (raised to any power) sum up to odd, adding the power of 2 still makes it odd

However, since we can group primes, we most likely will be grouping the smallest primes. There are 4 primes <sqrt100, 2 3 5 7. By grouping, we have 22 odd numbers and 2. 2 can be combined with an odd number leaving 21 odd numbers and one even number. The sum of that is odd. 1356 is even (?????????)

Possible explanation would be that the solution for 1356 involves -not- grouping one of 3, 5 or 7 and leaving it as its natural power. The most plausible is 3^4=81. Alternatively, there may be a case where there is a coprime which is the product of 3 primes