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Old 04-27-2016, 07:16 PM   #5
Pizza69
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Join Date: Aug 2013
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Default Re: Indices, Exponential and Logarithmic Equations

fifth: what are you getting hung up on? the 2? it looks like you've already been using alog(x) = log(x^a), so basically proceed as normal

base 4 2log(16)
= base 4 log(16^2)
= base 4 log(256)
= 4
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