[Reincarnate]

Originally Posted by LongGone

Stargroup originally came up with the idea that having a composite being a product of 3 primes isn't efficient and will never be part of the maximum set. I had a thought and will back this up by saying that, in order for a composite to be in the set it has to have at least two terms from group 1 (otherwise it will exceed n). And it is intuitively known to be not efficient to group together two sets of numbers from set 1 (as you remove the chance of it being paired up with a set 2 number, which is more efficient to produce larger composites. So I'll assume that the solution set involves composites with at most two distinct primes (raised to whatever power)

I think this is a reasonable assumption to make