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ieatyourlvllol · 08-4-2008, 05:20 PM

@Fractal: Yeah, you got the cyclical interval correct but forgot to subtract 11 from the coincidental positions [which fall at h:h(60/11)].

I was going to post an answer earlier, but you were close enough that it would have spoiled it for you. I think Emerald beat me to solving it, though.

A simple way to think of it is by separating the time frames of both hands into independent objects. Doing so yields twelve hours with twelve corresponding values (the count of which is tied to the clock parameters) whose angles/distances will be the same, resulting in 144 possible values. Remove 12:00 once (since 12 hours is singularly inclusive), then omit the 11 unique overlapping times to end up with 132.

EDIT: Ninja'd by Emerald

08-4-2008, 05:20 PM	#75
ieatyourlvllol FFR Player Join Date: Sep 2006 Location: it's a mystery oooo Posts: 3,221	Re: MrRubix's Riddle Thread @Fractal: Yeah, you got the cyclical interval correct but forgot to subtract 11 from the coincidental positions [which fall at h:h(60/11)]. I was going to post an answer earlier, but you were close enough that it would have spoiled it for you. I think Emerald beat me to solving it, though. A simple way to think of it is by separating the time frames of both hands into independent objects. Doing so yields twelve hours with twelve corresponding values (the count of which is tied to the clock parameters) whose angles/distances will be the same, resulting in 144 possible values. Remove 12:00 once (since 12 hours is singularly inclusive), then omit the 11 unique overlapping times to end up with 132. EDIT: Ninja'd by Emerald