[tha Guardians]

Originally Posted by RoyalCat

Infinity= I
Any Number= x

0*I=x
(0*I)^2=x^2

(0*I)^2= 0*0+0*I+0*I+I*I=I^2

I^2=x^2?
I=x?
Assuming that x is 0 then Infinity is 0. Or rather we can give infinity any value which would no longer make it infinity as someone previously stated, it isn't a real number. Then again that would break the premise for my whole calcluations since they regard the rules of math that work on actual numbers.

Going further;
0+I=I
(0+I)^2 is supposed to equal I^2

(0+I)^2= 0^2+2x+I^2= 2x+I^2

I^2= 2x+I^2
2x=0

Since 2 equals 2 which is not 0, then x must equal 0. Therefore, any number is always 0. Quite a big flaw.

Just some random thought. o_o

How does I*0=0? If you remove infinity from infinity, is it no longer infinity?

Originally Posted by Early Indian History, The Yajur Veda (1200-900 B.C.)

Om Poorna mada poorna midam (Om, that is full, this is full) Poornad poorna mudachyate (From that full, this full is removed) Poornasaya poornamadaya Poornameva vasishyate (Yet the full remains full always)"

It's like saying x-y=x=y, but x=I and y=I (sorry for expressing I with a variable, I realize that is incorrect)

I-I=/=0, I-I=?x or I-I=?I (but in my opinion, I-I=0+x = I-I=x because I (being me) believe Infinity = I+n^I (I has no limit, not because no limit is set, but because the limit increases infinitely)

I*2=2I, 2I=I, I*2=I

When you say Infinity zero times equals any number, do you say that because you don't know what Infinity zero times is?

(0^2=0)

2x+
(I^I=I, for infinity has no limit and shall always remain infinity)=
2x+I

EDIT: Please note that my theories are solely opinion and do not regard anyone other than myself and I do not state them as fact; only pure opinion.