# Line slope calculator 3x+7y=31

**Straight line given by points A[1; 4] and B[8; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.4286x+4.4286

**Canonical form of the line equation:**3x+7y-31 = 0

**Parametric form of the line equation:**

x = 7t+1

y = -3t+4 ; t ∈ R

**Slope:**m = -0.4286

**Slope angle of line: φ =**-23°11'55″ = -0.4049 rad

**X intercept:**x

_{0}= 10.3333

**Y intercept:**y

_{0}= q = 4.4286

**Distance line from the origin:**d

_{0}= 4.0705

**The length of the segment AB: |AB| =**7.6158

**Vector: AB =**(7; -3)

**Normal vector: n =**(3; 7)

**Midpoint of the segment AB: M =**[4.5; 2.5]

**Perpendicular Bisector equation:**7x-3y-24 = 0

**Vector OA = (1; 4) ; |OA| = 4.1231**

**Vector OB = (8; 1) ; |OB| = 8.0623**

**Scalar product OA .OB = 12**

**Angle ∠ AOB = 68°50'19″ = 1.2015 rad**