#### Answer

$(x+5)^2+(y+3)^2=5$

#### Work Step by Step

RECALL:
The standard equation of a circle whose center is at $(h, k)$ and has a radius of $r$ units is:
$(x-h)^2 + (y-k)^2 = r^2$
The given circle has its center at $(-5, -3)$ and a radius of $\sqrt5$ units.
Thus, the standard form of the circle's equation is:
$(x-(-5))^2+(y-(-3))^2=(\sqrt5)^2
\\(x+5)^2+(y+3)^2=5$