fruit math

[Frank Munoz]

Originally Posted by gold stinger

tl;dr of Frank's Post:

for all the people saying 17:
the bananas in the final equation are missing a banana each, and there's only 1 half of a coconut.

for all the people saying 14.5:
the apple in apple + banana + banana = 18 doesn't have a leaf like the rest of the apples

for all the people saying 14, 15, or 9:
how? You probably messed up on banana counting, coconut counting, or apple leaf counting somewhere.

edit:
here is answer:

A+A+A=30
30/3 = 10
A = 10
-------------------
a+B+B=18
-------------------
B-C=1
-------------------
(C/2)+A+((B/4)*3) = ??
(C/2)+10+((B/4)*3)

No one can find the answer to a, meaning you can't solve for B
and because you can't solve for B, you can't solve for C.
The only thing that you can solve is A.

OP changed the picture for some reason.
it used to be this

but is now this

though you are right,
it just makes my whole explanation that much more confusing.

thanks ilikexd

[Jtehanonymous]

19.5 maybe lol.

The apple with a leaf is 10 since 3 of them make thirty.

Now you have
a + 8B = 18 in the next line.
If I assume losing a leaf decreases the value of the apple with a leaf, a < 10.

If I assume B is an integer, the only possibilities for a single banana are 1 or 2. If B=1 then a = 10, but I think it should be less than 10 since it doesn't have a leaf.

Therefore, each Banana is 2? and then a = 2 so an apple without a leaf is only worth 2.

Moving along...line 3 has
4B - 2CH = 1

Each banana is 2 so 2 coconut halves should be 7.

Then 1 coconut half is 3.5?

Finally looking at the last line:
CH + Apple + 3B = 3.5 + 10 + 3(2) = 19.5


Lots of dumb assumptions and I'm upset with myself for even caring about this to begin with.

cry op playing with my heart nvm

[gold stinger]

Originally Posted by Frank Munoz

OP changed the picture for some reason.
it used to be this

Still wouldn't be able to solve shit even if you had the apple with a leaf & apple with no leaf swapping places. You would be able to solve the 2nd & 3rd questions sure, but you're leaving 2 variables in the 4th question. (One variable being ??, the other being the apple with no leaf.)

[leonid]

idk how to interpret that odd shaped apple

Actually scratch that lemme look at it again

[Frank Munoz]

In the new picture

technically, it's impossible to solve for a numerical answer... still.
because once again, though there are images similar to each other, they still do not match.
meaning they have a totally different(and unknown) value


solve for A
A+A+A=30
3A=30
(3A)/3=30/3
A=10


solve for B
a+B+B=18
a+2B=18
a/2+B=9
B=9-a/2

solve for a
a+B+B=18
a+2B=18
a=18-2B

solve for C
B-C=1
9-2a-C=1
-C=-8+2a
C=8-2a

solve for c
c+A+b=??
c+10+b=??
c+10=??-b
c=??-b-10

solve for b
c+A+b=??
c+10+b=??
10+b=??-c
b=??-c-10

solve for ??
c+A+b=??
??-b-10+10+??-c-10=??
2??-b-c+10=??
2??-b-c=??-10
2??-b=??-10+c
2??=??-10+b+c
??=b+c-10


You can try and speculate what they may average out to.
say,
c=C/2
and
b=B(3/4),
but the apple with no leaf(a) is still nonnumerical
meaning we can't solve for anything other than "A=10".

Another thing is to solve for zero, which i'll expand on later...
in short, there is no 'number' to solve for for now

[ilikexd]

I posted a long system of equations on my previous post--the answer is a function of the value of the leaf.

[Frank Munoz]

solving for 0
in the new picture

solve for A
A+A+A=30
3A=30
A=10

Solve for 0
a+B+B=18
a+2B-18=0

B-C=1
B-C-1=0

add
a+2B-18=0
to
B-C-1=0

a+3B-19=0

now solve for a
a+3B-19=0
a+3B=19
a=19-3B

then solve for B in the second equation
a+B+B=18
19-3B+B+B=18
19-3B+2B=18
19-B=18
-B=-1
B=1

GREAT, got B
now solve for a in the second equation
a+B+B=18
a+1+1=18
a+2=18
a=16

now back to the third equation
solve for C
B-C=1
1-C=1
-C=0
C=0

now to the last one which is tricky...
lets solve for 10
c+A+b=??
c+10+b=??
c+10=??-b
10=??-b-c
and as we know
10=A
so
A=??-b-c


now lets recap...
A=10 and 10=??-b-c
B=1
C=0
a=16
...

i gotta do my english hw now so i'll continue this ina bit

[Soundwave-]

I like how people are making assumptions.

These puzzles trip you into thinking that the point of the puzzle is to make assumptions to reach a certain "solution".

I simply reason that any answer within a field is correct, as the last equation contains three images that are unique to that equation. If you also felt the need to "solve" the images values themselves (which isn't strictly required), then the constraint would also be, of course, that your chosen elements also sum to your chosen solution.

So pi, 42, a matrix, and an expression that when graphed looks like your mom's chubby ass face are all correct answers.

[Frank Munoz]

Originally Posted by Soundwave-

So pi, 42, a matrix, and an expression that when graphed looks like your mom's chubby ass face are all correct answers.

Originally Posted by Frank Munoz

or, anything ranging from -infinity to infinity
as there is no real indication of the images being.. anything really.

....

[MinaciousGrace]

that argument is the ultimate cop out

and not even a clever one

[MinaciousGrace]

although i agree that it echoes the sentiment of the much more elegantly phrased

"moot frath"

[ilikexd]

Originally Posted by Frank Munoz

....

not fair that you limited your answer to only negative to positive infinity then

[Frank Munoz]

Originally Posted by ilikexd

not fair that you limited your answer to only negative to positive infinity then

infinity antimatter to infinity matter???

[Frank Munoz]

continuing this...

Originally Posted by Frank Munoz

solving for 0
in the new picture

solve for A
A+A+A=30
3A=30
A=10

Solve for 0
a+B+B=18
a+2B-18=0

B-C=1
B-C-1=0

add
a+2B-18=0
to
B-C-1=0

a+3B-19=0

now solve for a
a+3B-19=0
a+3B=19
a=19-3B

then solve for B in the second equation
a+B+B=18
19-3B+B+B=18
19-3B+2B=18
19-B=18
-B=-1
B=1

GREAT, got B
now solve for a in the second equation
a+B+B=18
a+1+1=18
a+2=18
a=16

now back to the third equation
solve for C
B-C=1
1-C=1
-C=0
C=0

now to the last one which is tricky...
lets solve for 10
c+A+b=??
c+10+b=??
c+10=??-b
10=??-b-c
and as we know
10=A
so
A=??-b-c


now lets recap...
A=10 and 10=??-b-c
B=1
C=0
a=16
...

i gotta do my english hw now so i'll continue this ina bit

now we just need to find
b
c and ??

the thing is, there's no way to connect b, c, or ?? to the other equations except for A, but A does not appear in anything except the first and last equations; this is where the main problem arises.
It nearly makes the second and third equations
completely...
ahem...
fruitless

since 10=??-b-c
and c+A+b=??
substituting A with it's new solution (??-b-c) in the last equation results in ??=??

c+A+b=??
c+??-b-c+b=??
??=??

since both sides are equal, there are -infinitely many- solutions. As stated previously in my past posts.

i'll look for a loophole in this later, gonna play vidyea games

[aperson]

okay but what's the dimension of the nullspace

[danceflashrevo]

Originally Posted by Soundwave-

So pi, 42, a matrix, and an expression that when graphed looks like your mom's chubby ass face are all correct answers.

let us fall down the rabbit hole god dammit

[YoshL]

did someone say rabbit

[danceflashrevo]

bun

[gold stinger]

It's time to solve for apple

First, we need to know what kind of apple we're dealing with.

What we have here, is a completely red apple, with a more or less solid green leaf. This means that the apple in question is an apple that grows into the red variety when ripe and does not stray from the red variety. There are a couple of apples out there that follow this routine, but looking at the most popular variety of apples, it's most likely either a Pink Crisp apple, Fuji apple, or Cameo apple, as the apple in the image is not as slender as Red Delicious apples are made out to be. However, a lot of people use Red Delicious apples as a base line image for interpreting the stock image of an apple, or the perfect apple (as attributed in the image of the equation we're attempting to solve).



Braeburn, Jazz, Cox, and Royal Gala apples tend to have slight pigment discolorations to show ripeness so they are most likely excluded from this scenario.

So right now, we have the most photogenic apple, the Fuji, the most commonly seen apple, Red Delicious, the most 'average' apple, the Cameo, and that guy, the Pink Crisp.

according to this link:


We are looking for a tree species of apple that most commonly suits the leaf that is shown in the original apple image. Using that, we can cross reference our suitable apples, and the kind of leaf that the tree comes with to make a closer interpretation to what exact species of 'red apple' that is being used for the equation. For this case, we're probably looking for either an ovate leaf, or an elliptical leaf since that is the one that is most likely used for the initial apple stock image when constructing the equation.

here's an image of a cameo apple tree:

an image of a red delicious apple tree:

Fuji:

Pink Crisp:

given these scenarios, we can probably rule out cameo apple completely, as the leaves from a cameo apple tree tend to lean towards a lanceolate style of leaf. There are some ovate leaves in there, but also codate, and oblong. We're looking for an apple where the prime majority can be identified as either ovate or elliptical.

Considering cameo apples, red delicious actually may be our best bet here, since the red delicious apple tree has a hampering towards elliptical style of leaves.

Fuji apple's main leaf is the cordate leaf in this image. So again, potential candidate is pointing towards the red delicious apple being the type of apple in the stock image, but hold onto your hats because:

Pink Crisp apples have elliptical leaves on their trees.

So who's the real winner here? Well, make up your own mind. Remember how I said Red Delicious apples are the most commonly referred to apple for images on the internet considering apples? Well, if you create that assumption, then the most likely apple in this case is a perfect, lump, Red Delicious apple, with an elliptical leaf attached to the stem.

So now we have a real world comparison:
= Red Delicious apple with elliptical leaf

figure it out from there, math freaks.

tl;dr I am 99% sure that the apple used in the equation is a Red Delicious breed of apple, with an elliptical leaf. Go nuts.

I can take it one step further and assume the apple is 170 grams (100 calories/perfect apple), but again, that's assumption.

[danceflashrevo]

Originally Posted by gold stinger

It's time to solve for apple

First, we need to know what kind of apple we're dealing with.

What we have here, is a completely red apple, with a more or less solid green leaf. This means that the apple in question is an apple that grows into the red variety when ripe and does not stray from the red variety. There are a couple of apples out there that follow this routine, but looking at the most popular variety of apples, it's most likely either a Pink Crisp apple, Fuji apple, or Cameo apple, as the apple in the image is not as slender as Red Delicious apples are made out to be. However, a lot of people use Red Delicious apples as a base line image for interpreting the stock image of an apple, or the perfect apple (as attributed in the image of the equation we're attempting to solve).



Braeburn, Jazz, Cox, and Royal Gala apples tend to have slight pigment discolorations to show ripeness so they are most likely excluded from this scenario.

So right now, we have the most photogenic apple, the Fuji, the most commonly seen apple, Red Delicious, the most 'average' apple, the Cameo, and that guy, the Pink Crisp.

according to this link:


We are looking for a tree species of apple that most commonly suits the leaf that is shown in the original apple image. Using that, we can cross reference our suitable apples, and the kind of leaf that the tree comes with to make a closer interpretation to what exact species of 'red apple' that is being used for the equation. For this case, we're probably looking for either an ovate leaf, or an elliptical leaf since that is the one that is most likely used for the initial apple stock image when constructing the equation.

here's an image of a cameo apple tree:

an image of a red delicious apple tree:

Fuji:

Pink Crisp:

given these scenarios, we can probably rule out cameo apple completely, as the leaves from a cameo apple tree tend to lean towards a lanceolate style of leaf. There are some ovate leaves in there, but also codate, and oblong. We're looking for an apple where the prime majority can be identified as either ovate or elliptical.

Considering cameo apples, red delicious actually may be our best bet here, since the red delicious apple tree has a hampering towards elliptical style of leaves.

Fuji apple's main leaf is the cordate leaf in this image. So again, potential candidate is pointing towards the red delicious apple being the type of apple in the stock image, but hold onto your hats because:

Pink Crisp apples have elliptical leaves on their trees.

So who's the real winner here? Well, make up your own mind. Remember how I said Red Delicious apples are the most commonly referred to apple for images on the internet considering apples? Well, if you create that assumption, then the most likely apple in this case is a perfect, lump, Red Delicious apple, with an elliptical leaf attached to the stem.

So now we have a real world comparison:
= Red Delicious apple with elliptical leaf

figure it out from there, math freaks.

tl;dr I am 99% sure that the apple used in the equation is a Red Delicious breed of apple, with an elliptical leaf. Go nuts.

I can take it one step further and assume the apple is 170 grams (100 calories/perfect apple), but again, that's assumption.

i admire your contributions; does someone have a working copy of photoshop so that we may analyze the pixel definitions of the apple so we can maybe solve for leaf?