[TheSaxRunner05]

Originally Posted by SKG_Scintill

that doesn't work

using 1 to 5, doing it twice before taking highest

[num1, num2]: highestnum
1,1: 1	2,1: 2	3,1: 3	4,1: 4	5,1: 5
1,2: 2	2,2: 2	3,2: 3	4,2: 4	5,2: 5
1,3: 3	2,3: 3	3,3: 3	4,3: 4	5,3: 5
1,4: 4	2,4: 4	3,4: 4	4,4: 4	5,4: 5
1,5: 5	2,5: 5	3,5: 5	4,5: 5	5,5: 5

[amount of combinations]
5^2 = 25

[number's amount of occurrences]
1: 1
2: 3
3: 5
4: 7
5: 9

[weight of numbers]
1: 1 * 1 = 1
2: 3 * 2 = 6
3: 5 * 3 = 15
4: 7 * 4 = 28
5: 9 * 5 = 45

[sum of weights]
1 + 6 + 15 + 28 + 45 = 95

[average] = [sum of weights] / [amount of combinations]

average: 95 / 25 = 3.8

using your formula:
0.5^(1/2)*4+1 = 3.8284~~~

I see, and since all answers will be rational numbers, using the square root function will fail. I can match one really close to the actual probabilities, but really close is like horseshoes and hand grenades in math lol

Thanks for going back and forth on this, I'm going to toy with the equation you posted a bit more.