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ilikexd · 07-26-2017, 04:16 PM

The EV of the highest number of N terms between 1 and 5 is the EV of the highest number of N-1 terms + 3/(2^N)

So when you start with 1 term between 1 and 5, you start with 3/(2^0)=3
3+3/(2^1)=4.5
4.5+3/(2^2)=5.25
etc.

Oh never mind, that's just wrong.

I need to adjust the numbers.

e: This ends up being the answer for numbers between 0 and 6 though.

07-26-2017, 04:16 PM	#13
ilikexd Join Date: Apr 2006 Posts: 3,205	Re: Math Question - Probability The EV of the highest number of N terms between 1 and 5 is the EV of the highest number of N-1 terms + 3/(2^N) So when you start with 1 term between 1 and 5, you start with 3/(2^0)=3 3+3/(2^1)=4.5 4.5+3/(2^2)=5.25 etc. Oh never mind, that's just wrong. I need to adjust the numbers. e: This ends up being the answer for numbers between 0 and 6 though. Last edited by ilikexd; 07-26-2017 at 04:30 PM..