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**sumzup** · 02-24-2008, 11:24 AM

Well, the OH (hydroxyl) group at the end is what facilitates hydrogen bonds to exist. CH4 doesn't have any hydrogen bonds; hydrogen bonds form with H in the presence of either O, N, or F. But now that I think about it, CH3OH may also be #1 because the OH group makes it polar as well, which contribute to its strength; thus, even though CCl4 has a much higher molar mass (which is a factor in bond strength), CH3OH is able to easily overcome that.

Another previous chemistry teacher of mine said that she would put CH4 < CO, so I'm not sure about that.

02-24-2008, 11:24 AM	#5
sumzup (+ (- (/ (* 1 2) 3) 4) 5) Join Date: Nov 2005 Location: Seattle Age: 33 Posts: 1,398	Re: [University - Chemistry] Intermolecular Forces Well, the OH (hydroxyl) group at the end is what facilitates hydrogen bonds to exist. CH4 doesn't have any hydrogen bonds; hydrogen bonds form with H in the presence of either O, N, or F. But now that I think about it, CH3OH may also be #1 because the OH group makes it polar as well, which contribute to its strength; thus, even though CCl4 has a much higher molar mass (which is a factor in bond strength), CH3OH is able to easily overcome that. Another previous chemistry teacher of mine said that she would put CH4 < CO, so I'm not sure about that.